Question

there is a structure called employee that holds information like employee code, name, date of joining. Write a program to create an array of the structure and enter some data into it. Then ask the user to enter current date. Display the names of those employees whose service is 15 or more than 15 years according to the given current date.

Answer 1

Answer:

The program in C is as follows:

#include<stdio.h>

#include<conio.h>

struct employee{

char empname[50]; int empcode, day,mon,yr;

}employees[30];

int main(){

int total;

printf("Numbers of Employees : "); scanf("%d",&total);

for(int kt=0;kt<total;kt++){

printf("Employee Code : "); scanf("%d",&employees[kt].empcode);

printf("Name: "); scanf("%s",employees[kt].empname);

printf("Date of Joining [dd mm yyyy]: "); scanf("%d%d%d",&employees[kt].day,&employees[kt].mon,&employees[kt].yr); }

int year;

printf("\nCurrent Date [Year only]: "); scanf("%d", &year);

printf("Code\t\t\t Name\t\t\t Date of Joining\n");

for(int kt=0;kt<total;kt++)

if((year - employees[kt].yr) >= 15)

printf("%d\t\t\t %s\t\t\t %d/%d/%d\n",employees[kt].empcode,employees[kt].empname, employees[kt].day,employees[kt].mon,employees[kt].yr);

}

Explanation:

See attachment for explanation where comments were used to explain some lines

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