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BigorU [14]
3 years ago
12

A qué se le conoce como el reactivo limitante

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
4 0
Answer : por que?

Step by step
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How many grams are in 3 mol of KBr?
e-lub [12.9K]

Answer: 7

Explanation:

6 0
4 years ago
Read 2 more answers
I NEED HELP ASAP !
Lana71 [14]

Answer:

1.

643.21g  1 mol  6.022^23

262.87 g   1 mol

= 1.4735E24     [Mg3(PO4)2]

2.

4.061x10^24          1mol                22.4 (L)  

6.022^23       1mol

= 151 liters H2O2

3.

479.3g   1 mol   6.022^23

18.02g    1mol

= 1.60E25 H20 atoms

4.

80.34L   1mol       164.1

22.4L       1mol

588.6g   Ca(NO3)2

5.

893.7g   1mol       22.4

44.01g   1mol

= 427 L CO2 or 427.4

6.

5.39 x 10^25     1mol     78.01

6.022^23    1mol

= 6980g Al(OH)3

hope this helps!! :)

8 0
3 years ago
A sample of paper from an ancient scroll was found to contain 39.5% 14C content as compared to a present-day sample. The t1/2 fo
nirvana33 [79]

Answer

7665 years

Procedure

Let N₀ be the amount of carbon-14 present in a living organism. According to the radioactive decay law, the number of carbon-14 atoms, N, left in a dead tissue sample after a certain time, t, is given by the exponential equation:

N = N₀e^(-λt)

where λ is the decay constant which is related to half-life (T1/2) by the equation:

\lambda=\frac{ln(2)}{t_{\frac{1}{2}}}

Here, ln(2) is the natural logarithm of 2.

The percent of carbon-14 remaining after time t is given by N/N₀.

Using the first equation, we can determine λt.

The half-life of carbon-14 is 5,720 years, thus, we can calculate λ using the second equation, and then find t.

\lambda=\frac{ln(2)}{5720}=1.211\times10^{-4}

Solving the second equation for t, and using the λ we have just calculated we will have

t= 7665 years

3 0
1 year ago
Find the density of a material given that a 5.03g sample occupies 3.24ml
Verizon [17]

Formula for density:

D = Mass / Volume

Mass = 5.03g

Volume = 3.24ml


Formula in our case:

D = 5.03 / 3.24

D = 0.31~g/m^{3}


Hope it helped,


BioTeacher101

3 0
4 years ago
If a match were placed in the cone close to the barrel of the gas burner will it ignite
Pani-rosa [81]
I think it would seeing as you typicaly have to use a match to light a gas burner
8 0
3 years ago
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