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SIZIF [17.4K]
3 years ago
7

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane

d from the third postulate in Dalton's series. Magnesium oxide decomposes into magnesium and oxygen. If 16.12 g of magnesium oxide decomposes to form 9.72 g of magnesium, what mass of oxygen gas is also released in the reaction?
Chemistry
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2MgO\rightarrow 2Mg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2MgO = Total mass of 2Mg+O_2

or,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

As we are given :

Total mass of MgO = 16.12 grams

The mass of Mg = 9.72 grams

So,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

2\times 16.12g=2\times 9.72g+\text{Mass of }O_2

\text{Mass of }O_2=32.24g-19.44g=12.8g

Therefore, the total mass of oxygen gas released in the reaction will be, 12.8 grams

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I need help with my work
elena-14-01-66 [18.8K]

Answer:

2 the mass is greater than 10.0gram

Explanation:

2 the mass is greater than 10.0gram

8 0
2 years ago
Initial alcohol is converted to compound A. Compound A undergoes three different transformations. Name compound A and each the f
nikklg [1K]
<h2>Acetic Acid</h2>

Explanation:

  • Initial alcohol that is formed from methane is methanol that can be converted to acetic acid.
  • Methanol in presence of CO_2 and hydrogen gas gets oxidized to acetic acid with the release of water.

Hence, compound A will be Acetic acid.

CH_3OH + CO_2 +H_2 → CH_3COOH + H_2O

  • The acetic acid formed can be transformed into -
  1. CH_3COOH → CH_4 + CO

        The product formed is methane and carbon monoxide.

    2. CH_3COOH → CH_2CHO + H_2O

         The product formed is formaldehyde and water.

    3. CH_3COOH + NaHCO_3 → CH_3COONa +CO_2 +H_2O

         The product formed is sodium acetate, carbon dioxide, and water.

4 0
3 years ago
How many joules of energy are made by the loss of 100kg of mass using the formula E=mc2? please help!!!
asambeis [7]

Answer:

E = 3 × 10¹⁰ J

Explanation:

Mass, m = 100 kg

We need to find energy made by the loss of 100 kg of mass. The formula between the mass and energy is given by :

E = mc²

Where c is speed of light

Putting all the values, we get :

E = 100 kg × (3×10⁸ m/s)²

= 3 × 10¹⁰ J

So, the required energy is 3 × 10¹⁰ J.

6 0
3 years ago
A 254.5 g sample of a white solid is known to be a mixture of KNO3, BaCl2, and NaCl. When 116.5 g of this mixture is dissolved i
Margaret [11]

Answer:

Mass of KNO3 in the original mix is 146.954 g

Explanation:

mass of KNO_3 in original  254.5 mixture.

moles of BaSO_4 = \frac{mass}{Molecular\ Weight}

moles ofBaSO_4  = \frac{68.3}{233.38}

                               = 0.2926 mol of BaSO4

Therefore,

0.2926 mol of BaCl2,

mass of BaCl_2 = mol\times molecular weight

                         = 0.2926\times 208.23

                         = 60.92 g

the AgCl moles = \frac{mass}{Molecular\ Weight}

                          = \frac{199.1}{143.32}

                          = 1.3891 mol of AgCl

note that, the Cl- derive from both, BACl_2 and NaCl

so

mole of Cl- f NaCl = (1.3891) - (0.2926\times 2) = 0.8039 mol of Cl-

mol of NaCl = 0.8039 moles

mass = mol\times Molecular\ Weight  = 0.8039 \times 58 = 46.626\ g \ of \ NaCl

then

KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3

Mass of KNO3 in the original mix is 146.954 g

8 0
3 years ago
8.03 Solutions Lab Report<br> Does anyone have a PDF or Document of FLVS 8.03 Solutions Lab
GarryVolchara [31]

8.03 solutions report is described below.

Explanation:

8.03 Solutions Lab Report

In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.  

Pre-lab Questions:

In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.  

Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).

Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.

7 0
3 years ago
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