1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SIZIF [17.4K]
2 years ago
7

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane

d from the third postulate in Dalton's series. Magnesium oxide decomposes into magnesium and oxygen. If 16.12 g of magnesium oxide decomposes to form 9.72 g of magnesium, what mass of oxygen gas is also released in the reaction?
Chemistry
1 answer:
GenaCL600 [577]2 years ago
8 0

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2MgO\rightarrow 2Mg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2MgO = Total mass of 2Mg+O_2

or,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

As we are given :

Total mass of MgO = 16.12 grams

The mass of Mg = 9.72 grams

So,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

2\times 16.12g=2\times 9.72g+\text{Mass of }O_2

\text{Mass of }O_2=32.24g-19.44g=12.8g

Therefore, the total mass of oxygen gas released in the reaction will be, 12.8 grams

You might be interested in
Determine the mass in grams of each nacl solution that contains 1.5g of nacl
Rama09 [41]

Answer:- 3333 g of solution.

Some of the question part is missing here. It would be like, "Determine the mass in grams of each NaCl solution that contains 1.5 g of NaCl.

(i) 0.045% NaCl by mass

Solution:- 0.045% NaCl by mass means 0.045 g of NaCl are present in 100 g of solution. 1.5 g of NaCl would be present in how many grams of solution?

We could solve this using proportions...

(0.045/100) = (1.5/X)

0.045(X) = 1.5(100)

0.045X = 150

X = 150/0.045 = 3333

So, 1.5 g of NaCl is present in 3333 g of solution.

7 0
3 years ago
Why is potasium oxide not used to investigate property of hydrogen gas​
Anarel [89]

Because potassium is more reactive than hydrogen

3 0
3 years ago
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
To which group of the periodic table do lithium and potassium belong?
s344n2d4d5 [400]

Answer:

1)alkali metals

2)1g/ml

3) mercury

Explanation:

<em><u>HEY!</u></em><em><u>!</u></em><em><u>^</u></em><em><u>^</u></em>

<em><u>have </u></em><em><u>a </u></em><em><u>good </u></em><em><u>day</u></em>

<em><u>thank </u></em><em><u>me </u></em><em><u>later</u></em>

<em><u>carryonlearing </u></em>

6 0
2 years ago
Read 2 more answers
Name the separation technique illustrated in the picture<br>​
o-na [289]
The picture isn’t included
3 0
2 years ago
Other questions:
  • A beaker containing a mixture of N2(g) and H2(g) is cooled by placing it in a tray of cold water. In response to the cooling, th
    7·2 answers
  • PLEASE HELP!!! I am taking a college chem class as a junior and have no idea how to do this!
    10·1 answer
  • Element
    5·1 answer
  • What is equivalent to a drink made with 3 ounces of 80 proof vodka?
    11·1 answer
  • A rock has a mass of 210 grams and occupies a volume of 70 cm3. What is its density?
    10·1 answer
  • 50 POINTS! <br><br><br><br>Which SIX statements are correct about CELLULAR RESPIRATION?
    15·2 answers
  • Chemical equations
    10·2 answers
  • Consider the following balanced equation: 5O2(g) + C3H8(g) → 3CO2(g) + 4H2O(l) If 24.9 moles of O2(g) and 6.85 moles of C3H8(g)
    5·1 answer
  • Cu + O2 --Cu2O
    9·1 answer
  • What would be the answer
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!