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MrMuchimi
2 years ago
5

Can someone please help me find the answer and explain it to me I would really appreciate it !

Mathematics
1 answer:
ziro4ka [17]2 years ago
7 0
47 due to the moon and moon moon and the park random park in the west clan center west
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A number is chosen at random from 1 to 10. Find the probability of selecting factors of 4 and factors
Lena [83]
The ANWSER is 2/4 I hope I helped
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3 years ago
Help me please I don’t know this
Afina-wow [57]
The answer is the number will have to be less than 11 which means that it is a. 9
sorry if it is incorrect.
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Which measurement below has four significant figures? A. 14,052 km B. 12.05 L C. 0.0230 kg D. 12.501 m
Dmitrij [34]
The answer is B 12.05L
5 0
3 years ago
A bag of chips is 24 ounces. A serving size is 3/4 ounce. How many servings are in the bag of chips?
marysya [2.9K]

Answer:

The correct answer to the following question will be "32 servings".

Step-by-step explanation:

The given values are,

A bag of chips = 24 ounces

Serving size = 3/4 ounces

Servings = ?

Now,

On dividing "24 ounces" by "3/4 ounce", we get

⇒  \frac{24}{\frac{3}{4}}

⇒  24\times \frac{4}{3}

⇒  8\times 4

⇒  32

Thus, the bag of chips contains "32" servings.

4 0
3 years ago
A club consists of 21 Republicans and 25 Democrats. If four people are chosen at random to be on a​ committee, what is the proba
Allushta [10]

Answer:

88.58% probability that at least one person from each political party will be​ chosen

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Also, the order which the people are chosen is not important. So the combinations formula is used to solve this problem.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

If four people are chosen at random to be on a​ committee, what is the probability that at least one person from each political party will be​ chosen?

Either only Republicans or Democrats are chosen, or at least one member from each party is chosen. The sum of these probabilities is 100%.

The easier way to solve this is first finding the probability that members are only from one party.

Probability of having members from only one party:

Desired outcomes:

Only Democrats:

4 from a set of 25.

Only Republican:

4 from a set of 21.

So

D = C_{25,4} + C_{21,4} = \frac{25!}{4!21!} + \frac{21!}{4!17!} = 18635

Total outcomes:

4 from 21+25 = 46 total members

T = C_{46,4} = \frac{46!}{4!42!} = 163185

Probability:

p = \frac{D}{T} = \frac{18635}{163185} = 0.1142

11.42% probability of having people from only one party in the committee

Probability of at least one person from each party:

p + 11.42 = 100

p = 88.58

88.58% probability that at least one person from each political party will be​ chosen

5 0
3 years ago
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