The graph shows the height (h), in feet, of a basketball t seconds after it is shot. Projectile motion formula: h(t) = -16t2 + v
t + h0 v = initial vertical velocity of the ball in feet per second h0 = initial height of the ball in feet Complete the quadratic equation that models the situation. h(t) = –16t2 + t + 6 Image description
2 answers:
Answer:
h(t) = –16t^2 + 46*t + 6
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The projectile formula is
h(t) = -16*t^2 + v*t + h0
Where,
v = initial vertical velocity of the ball in feet per second
h0 = initial height of the ball in feet
We need to fill the equation
h(t) = –16t^2 + v*t + 6
Where
v is the missing speed
If we go through many values of v until we find the same graph as the one showed in the first picture, we can find that
v = 46 ft/s
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