The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
Answer:
1125 times bigger
Step-by-step explanation:
Simplify both sides of the equation.
<span><span>25−n</span>=32
</span><span>Simplify:
</span><span><span><span>−n</span>+25</span>=32
</span>Subtract 25 from both sides.
<span><span><span><span>−n</span>+25</span>−25</span>=<span>32−25
</span></span><span><span>−n</span>=7
</span>Divide both sides by -1.
<span><span><span>−n/</span><span>−1 </span></span>= <span>7/<span>−1
</span></span></span><span>n=<span>−7
</span></span>Ans:
<span>n = <span>−7</span></span><span>
</span>
Answer:
89
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
