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k0ka [10]
2 years ago
10

Determine the value of a + b in the system of equations below. 5a + 4b = 22 7a-b= 11

Mathematics
1 answer:
dexar [7]2 years ago
6 0

Answer:

We have a + b as;

2 + 3 = 5

Step-by-step explanation:

Here, we want go get the value of a and b

from the second equation, we can get an expression for b

We have this as;

7a - b = 11

Thus,

b = 7a - 11

Now, from here, we can substitute the value of b into the first equation

We have this as;

5a + 4(7a - 11) = 22

5a + 28a -44 = 22

33a = 22 + 44

33a = 66

a = 66/33

a = 2

Recall;

b = 7a - 11

substituting the value of a from above;

b = 7(2) - 11

b = 14 - 11

b = 3

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Helpppp me plz i dont get it
SOVA2 [1]
Try 3.14x2= 6.28 im so sorry if its wrong
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A painting has an area of 108 square inches. The dimensions of the painting are 12 and x + 3. What is the perimeter of the paint
slega [8]

Answer:

108 divide 12 and i got 9

then i did 9-3 and i got 6.

12+12+9+9=42

So the perimeter is 42

Welp i don't know if it is correct or not

Step-by-step explanation:

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2 years ago
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Which is an x-intercept of the continuous function in the table?
Airida [17]

we know that

The x-intercept is the value of the variable x when the value of the function is equal to zero

so

In the table we have

(-1, 0) is a x-intercept, because

For x=-1 the value of the function is equal to zero

(-6, 0) is a x-intercept, because

For x=-6 the value of the function is equal to zero

therefore

<u>the answer is</u>

the continuous function in the table has two x-intercepts

(-1, 0)

(-6, 0)

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3 years ago
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What is the difference between the absolute value of 4 and the absolute value of –3?
Sergeeva-Olga [200]
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the absolute value of (-3) is 3
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2 years ago
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The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
2 years ago
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