All categories

3 years ago

Halppppppp meeeaaaaaaaaaaaa

Mathematics

1 answer:

zvonat [6]3 years ago

7 0

Answer:

The x-intercept is the location on the graph when the output is 0.

f(x) > 0 is intervals of the domain where the graph is above the x-axis.

y-intercept is the location on the graph when the input is 0.

f(x) < 0 is intervals of the domain where the graph is below the x-axis.

You might be interested in

Add.

Hoochie [10]

You add each number that is in the same position correlated to the box. Ex: 12+-3=9

7 0

3 years ago

Read 2 more answers

A package of 5 pairs of insulated socks costs $26.45. What is the unit price of the pairs of socks?

tigry1 [53]

Answer:

$5.29 per pair of socks

Step-by-step explanation:

26.45/5=5.29

3 0

2 years ago

En el experimento Extraer una carta de una baraja española se consideran estos sucesos: A= 《Salir as 》 B= 《salir bastos 》 Calcul

Ganezh [65]

Answer:

They are compatible

Step-by-step explanation:

The first thing is to say that an "ace" and that it is a "coarse"

"ace" is card number 1. Group A

"coarse" is a type of the deck, found from number 1 to card 13. Group B

Thus:

Calculate A U B:

1 to 13 + 1 of the other types of cards in the deck.

At intersection B:

1 of "coarse"

Therefore, if group A is compatible with group B

7 0

3 years ago

What is the slope of the line passing through the points (2,7) and (-1,3)?

e-lub [12.9K]

The slope of the line is 4/3

5 0

3 years ago

the equation of a circle in general form is x squared + y squared + 20x + 12 y + 15 equals 0what is the equation of the circle i

Marrrta [24]

Answer: $(x+10)^2+(y+6)^2=121$

Step-by-step explanation:

The equation of a circle in the general form is:

$ax^{2}+by^2+cx+dy+e=0$

The equaton of a circle in standard form is:

$(x-h)^2+(y-k)^2=r^2$

Where the center is at <em>(h, k)</em> and <em>r</em> is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

$x^{2}+y^2+20x+12y+15=0$

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

$(x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121$

4 0

3 years ago