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vova2212 [387]
3 years ago
11

Halppppppp meeeaaaaaaaaaaaa

Mathematics
1 answer:
zvonat [6]3 years ago
7 0

Answer:

The x-intercept is the location on the graph when the output is 0.

f(x) > 0 is intervals of the domain where the graph is above the x-axis.

y-intercept is the location on the graph when the input is 0.

f(x) < 0 is intervals of the domain where the graph is below the x-axis.

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What is the value of x in the solution to the following system of equations?
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The formula d= rt gives the distance traveled in time t at rate r. A delivery truck drives for 1.5 hours and travels 76miles.
Alika [10]

The formula d = rt describes distance traveled in time and rate of speed. However, we only have the distance and time to place in. This means d = rt would become d / t = r. Once filled in, the problem is now 76 / 1.5 which equals 50.6 (repeating bar over the 6). However, this is the AVERAGE speed of the truck (meaning we are rounding. 50.6 rounded to the nearest speed would be 51 miles per hour.

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(a) 3n – 11 &gt; 5n – 18
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Answer:

Step-by-step explanation:

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3 years ago
Kevin runs 4 miles in 30 minutes. At the same rate, how many miles would he run in 48 minutes?
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5 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

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3 years ago
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