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sergeinik [125]
3 years ago
11

(True or False) The table below is a function.

Mathematics
1 answer:
Svetach [21]3 years ago
7 0

Answer:

False

Step-by-step explanation:

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As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
Which graph is the graph for the function? <br><br> y=x^2+x-12
LenaWriter [7]

Answer:

The top one because it is decresing by 12

Step-by-step explanation:

3 0
3 years ago
Find the percent of discountOriginal price Sale Price<br> $60 <br> % $45
qwelly [4]

Answer:

25% Discount

Step-by-step explanation:

find the percent of discountOriginal price Sale Price

$60

% $45 =

$60 was the SP

$45 is the MP

discount = 60/45 * 100 = 75

100 - 75 = 25%

8 0
2 years ago
Madison is baking party favors she wants to make enough favor so each guest gets the same number of favors she knows there will
iris [78.8K]

Answer:

It would be 24

Step-by-step explanation:

6: 6, 12, 18, 24

8: 8, 16, 24

The least common number is 24, so she should make at least 24.

4 0
3 years ago
The area of a regular octagon is 35 cm^2. What is the area of a regular octagon with sides five times as long?
Marat540 [252]
So... let's say the smaller regular octagon has sides of "x" long, then the larger octagon will have sides of 5x.

\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array} \\\\&#10;-----------------------------\\\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{small}{large}\quad \stackrel{area~ratio}{\cfrac{s^2}{s^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{(5x)^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{5^2x^2}}\implies \stackrel{area~ratio}{\cfrac{\underline{x^2}}{25\underline{x^2}}}=\stackrel{area~ratio}{\cfrac{35}{a}}&#10;\\\\\\&#10;\cfrac{1}{25}=\cfrac{35}{a}\implies a=\cfrac{25\cdot 35}{1}
3 0
3 years ago
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