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2 years ago

6

[50 POINTS] WILL MARK BRAINLIEST!!! Please solve the whole page with work!! It will be very much appreciated and I will heart th

e correct comment and give it 5 stars

1 answer:

Gre4nikov [31]2 years ago

4 0

Answer:

wait, it only 25 points...

Step-by-step explanation:

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Distributive property 7(2n+3)

Black_prince [1.1K]

its 14n+21. 7×2n is 14n, and 3×7 is 21

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3 years ago

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Write the equation y-7= 2(x + 1) in standard form.

Andru [333]

Answer:

y=2X+9

Step-by-step explanation:

y-7=2(x+1)

Distribute 2 through: y-7=2x+2

Add 7 over to the other side: y=2x+9

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2 years ago

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If 4 pairs of socks costs $10. 00, how many pairs of socks can be purchased for $22. 50?.

klasskru [66]

9 pairs.

If 4 pairs of socks cost $10.00 and you have $22.50 to spend then you can buy 9 pairs of socks leaving you with $0.00 left over.
Each pair of socks cost $2.50.

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2 years ago

If a random sample of size nequals=6 is taken from a population, what is required in order to say that the sampling distributio

goldenfox [79]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we want a normal distribution for the sample mean

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

$X_i \sim N(\mu , \sigma), i=1,2,...,n$

Because if we find the parameters we got:

$E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu$

$Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}$

And the deviation would be:

$Sd (\bar X) = \frac{\sigma}{\sqrt{n}}$

And we satisfy the condition:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

3 0

2 years ago

6<br> Rewrite<br> as a mixed number.<br> =

anastassius [24]

Answer:

=7/1

Step-by-step explanation:

brainliest?

8 0

2 years ago