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xz_007 [3.2K]
3 years ago
5

The line L1 has equation 2x+y=8.The line L2 passes through the point A(7,4) and is perpendicular to L1.

Mathematics
1 answer:
baherus [9]3 years ago
4 0
If m1 and m2 are the slopes of each line, for them to be perpendicular you gotta solve
m1 * m2 = -1
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Match each expression with the equivalent expanded expression.
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Question

Match each expression with the equivalent expanded expression.

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Answer:



Step-by-step explanation:



Step-by-step explanation:

Question

Match each expression with the equivalent expanded expression.

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- 10x - 3

1/3 ( 9 +81)

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2 (4x-2)

x + 1.5

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Step-by-step explanation:



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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
VARVARA [1.3K]

Answer:

\displaystyle    - 155

Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

the given function is in the standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

so we acquire:

  • b=30
  • a=-5

thus substitute:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

simplify multiplication:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{ - 10}

simply division:

\displaystyle x _{ \rm  min} =  3

plug in the value of minimum x to the given function:

\displaystyle f (3)=  - 5 {(3)}^{2}  + 30.3 - 200

simplify square:

\displaystyle f (3)=  - 5 {(9)}^{}  + 30.3 - 200

simplify multiplication:

\displaystyle f (3)=  - 45  + 90- 200

simplify:

\displaystyle f (3)=   - 155

hence,

the minimum value of the function is -155

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