3x=2(5x-1)=11
3x=10x-2=11
-10x -10x
-------------------
-7x=-2=11
+2 +2
------------------
-7x=13
----- ------
-7 -7
x= -1.9
a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
Distance between Station E and Station G is 8.48 miles (Approx.)
<u>Given:</u>
Distance 3 miles east
Distance 5 miles south
<u>Find:</u>
Distance between Station E and Station G
<u>Computation:</u>
Co-ordinate of Point E = (-3 , 1)
Co-ordinate of Point G is 3 mile east and 5 mile south
So,
Co-ordinate of Point G = (3 , -5)
Distance between two point = √(x2 - x1)² + (y2 - y1)²
So,
Distance between Station E and Station G = √(3 + 3)² + (-5 - 1)²
Distance between Station E and Station G = √(6)² + (-6)²
Distance between Station E and Station G = √36 + 36
Distance between Station E and Station G = √72
Distance between Station E and Station G = 8.48 miles (Approx.)
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brainly.com/question/12052812?referrer=searchResults
6×12 = 72
72 - (3x3) = 63
63 in ^2
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