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GREYUIT [131]
3 years ago
12

Is c=5t proportional or nonproportional

Mathematics
1 answer:
otez555 [7]3 years ago
4 0

Answer:

Proportinal

Step-by-step explanation:

The y is 0

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On a typical day flights at a local airport arrive at a rate of 10 every 15 minutes at this rate how many flights would you expe
pogonyaev
40 flights, you could use rates in this situation. 
15 min*4=60 min=1 hr
10:15 multiply each side by 4
40 flights:60 minutes

4 0
3 years ago
SOMEONE HELP! (b+3)(c-4)
choli [55]

Answer

bc - 4b + 3c - 12

solution,

(b + 3)(c - 4) \\  = b(c - 4) + 3(c - 4) \\  = bc - 4b + 3c - 12

hope it helps..

7 0
3 years ago
Read 2 more answers
The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit
jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

f(x) = \lambda e^{-\lambda x} ; x > 0

Here, \lambda = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean =  \frac{1}{\lambda}  

So,  22=\frac{1}{\lambda}  ⇒ \lambda=\frac{1}{22}

SO, X ~ Exp(\lambda=\frac{1}{22})  

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

    P(X\leq x) = 1 - e^{-\lambda x}  ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

        P(X < 30)  =  1 - e^{-\frac{1}{22} \times 30}

                         =  1 - 0.2557

                         =  0.7443

7 0
3 years ago
What is a equivalent ratio of 16:18
Elis [28]

equivalent ratio of 16:18 is 8:9

6 0
3 years ago
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Simplify<br> 4-3[6-2(4-3)]
ikadub [295]

Answer:

<h2>-8</h2>

Step-by-step explanation:

4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8

4 0
3 years ago
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