Answer:
Step-by-step explanation:
(7x-5)(6x+10)=0
42x + 70x - 30x - 50 = 0
82x = 50
x = 50/82
Answer:
23
Step-by-step explanation: Substitute 1 for p & 7 for q
7 − 5p + 3q
7 - 5(1) + 3(7)
7 - 5 + 21
7 + 16
23
Hope this helps you!!! :)
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)
Answer:
Step-by-step explanation:
Lets see... Miles per gallon...Miles/gallon...425 miles/12.6 gallons = 33.73 miles/gallon = 33.73 miles per gallon
Answer:
Step-by-step explanation:
Let's say the number "n" were the largest multiple of 9. But then:
Consider n + 9. n is itself a multiple of 9, so n = 9k, so n + 9 = 9(k + 1), so n + 9 is also a multiple of 9, and n + 9 is larger than n.
So there can't be a largest multiple of 9 (or any number).