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Maurinko [17]
3 years ago
13

PLEASE HELP

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Step-by-step explanation:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Damm [24]3 years ago
6 0

Answer:

b = 1.7

c = 7.1

Step-by-step explanation:

the triangle with side 'b' is a 30-60-90° Δ where the ratio of sides, respectively, are 1 : \sqrt{3} : 2

to find 'b' we could set up this proportion:

b/3 = 1/\sqrt{3}

cross-multiply:

b\sqrt{3} = 3

b = 3 / \sqrt{3}

if we rationalize the denominator, this becomes (3\sqrt{3})/3 which is \sqrt{3} or 1.7

the other triangle is a 45-45-90°Δ where the ratio of the sides are 1 : 1 : \sqrt{2}

if the legs are 5 then the hypotenuse is 5\sqrt{2} or 7.1

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2) In the case of SSA, when the given angle A is acute (<90°), the side "a" (opposite to the given angle "A") is less than the other given side "b" (a<b), and a > b sinA.  

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4.2) Direction of vector AB=348.69°  

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6.1) Trigonometric form: z = 3√2 (cos 315°+ i sin 315°)  

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Step-by-step explanation:

3.1) Perimeter: P = a+b+c → P = 10+6+15.37 → P = 31.37  

Area: A = a b sinC / 2

Replacing the known values:

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Area: A = a b sin C /2

Replacing the known values:

A = (32)(6) sin 123.99036327° / 2 → A = 192(0.82913161) / 2 →

A = 75.59663485 → A = 75.6 square units

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