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3 years ago

PLEASE HELP

Mathematics

2 answers:

tekilochka [14]3 years ago

7 0

Answer:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Step-by-step explanation:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Damm [24]3 years ago

6 0

Answer:

b = 1.7

c = 7.1

Step-by-step explanation:

the triangle with side 'b' is a 30-60-90° Δ where the ratio of sides, respectively, are 1 : $\sqrt{3}$ : 2

to find 'b' we could set up this proportion:

b/3 = 1/ $\sqrt{3}$

cross-multiply:

b $\sqrt{3}$ = 3

b = 3 / $\sqrt{3}$

if we rationalize the denominator, this becomes (3 $\sqrt{3}$ )/3 which is $\sqrt{3}$ or 1.7

the other triangle is a 45-45-90°Δ where the ratio of the sides are 1 : 1 : $\sqrt{2}$

if the legs are 5 then the hypotenuse is 5 $\sqrt{2}$ or 7.1

You might be interested in

In a group of 60 students, 12 students take algebra one, 18 students take algebra 2 and 8 students take both subjects how many s

hoa [83]

60-12-18-2-8=20
=48-18-2-8
=30-2-8
=28-8
=20

So, 20 students don't take either of these subjects.

5 0

3 years ago

What 2 numbers add to get 2 and multiply to 4

rusak2 [61]

Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x= $\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a}$ so

1x^2-2x+4=0
a=1
b=-2
c=4
x= $\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}$
x= $\frac{ 2+/-\sqrt{4-16} }{2}$
x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x= $\frac{ 2+/-2\sqrt{-3} }{2}$
i= $\sqrt{-1}$
x= $\frac{ 2+/-2i\sqrt{3} }{2}$
x= $1+/-i\sqrt{3}$
x= $1-i\sqrt{3}$ or x= $1+i\sqrt{3}$ (those are the 2 numbers)

6 0

3 years ago

Y=0.5x+3.5 on graphs

tresset_1 [31]

You should go up 3.5 on the Y-Axis and then go up .5 and over 1.

5 0

3 years ago

WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7

Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!$\*SuperscriptBox[\(Base$, $Power$]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0

2 years ago

Can you help me please?

9966 [12]

First, change the two mixed numbers in the expression into an improper fraction: 25/6 + 5/3.
Then, find the Lowest Common Denominator of both fractions, which is 6, and set both denominators equal to that. Remember, whatever you do on one side you must do to the other: 25/6 + 10/6
Add the two together: 25/6 +10/6 = 35/6.
To make it a mixed number again, find how many times 6 goes into 35, which is 5 times, with a remainder of 5. Your answer is 5 5/6

6 0

3 years ago