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2 years ago

PLEASE HELP

Mathematics

2 answers:

tekilochka [14]2 years ago

7 0

Answer:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Step-by-step explanation:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Damm [24]2 years ago

6 0

Answer:

b = 1.7

c = 7.1

Step-by-step explanation:

the triangle with side 'b' is a 30-60-90° Δ where the ratio of sides, respectively, are 1 : $\sqrt{3}$ : 2

to find 'b' we could set up this proportion:

b/3 = 1/ $\sqrt{3}$

cross-multiply:

b $\sqrt{3}$ = 3

b = 3 / $\sqrt{3}$

if we rationalize the denominator, this becomes (3 $\sqrt{3}$ )/3 which is $\sqrt{3}$ or 1.7

the other triangle is a 45-45-90°Δ where the ratio of the sides are 1 : 1 : $\sqrt{2}$

if the legs are 5 then the hypotenuse is 5 $\sqrt{2}$ or 7.1

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motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

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The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

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Sveta_85 [38]

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