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Maurinko [17]
3 years ago
13

PLEASE HELP

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Step-by-step explanation:

PLEASE HELP

For the right triangles below, find the values of the side lengths b and c.

Round your answers to the nearest tenth.

Damm [24]3 years ago
6 0

Answer:

b = 1.7

c = 7.1

Step-by-step explanation:

the triangle with side 'b' is a 30-60-90° Δ where the ratio of sides, respectively, are 1 : \sqrt{3} : 2

to find 'b' we could set up this proportion:

b/3 = 1/\sqrt{3}

cross-multiply:

b\sqrt{3} = 3

b = 3 / \sqrt{3}

if we rationalize the denominator, this becomes (3\sqrt{3})/3 which is \sqrt{3} or 1.7

the other triangle is a 45-45-90°Δ where the ratio of the sides are 1 : 1 : \sqrt{2}

if the legs are 5 then the hypotenuse is 5\sqrt{2} or 7.1

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Find the value of x.<br> 16.2<br> 0.03<br> 38.5<br> 34.8
ella [17]

Hi there!

\large\boxed{x = 38.5}}

To solve, we can use right triangle trig.

We are given the value of ∠A, and side "x" is its adjacent side. We are also given its opposite side, so:

tan (A) = O / A

tan (33) = 25 / x

Solve:

x · tan(33) = 25

x = 38.49 ≈ 38.5

7 0
3 years ago
Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare
leva [86]

Answer: x+3y=12

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is y=3x, then its slope = 3   [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}

Equation of line with slope n and passers through (a,b) is

(y-b)=n(x-a)

Equation of line with slope n= \dfrac{-1}{3} and passes through point ( 0,-4) :

(y-(-4))=\dfrac{-1}{3}(x-0)\\\\\Rightarrow\ y+4=\dfrac{-1}{3}x\\\\\Rightarrow\ -3(y+4)=x\\\\\Rightarrow-3y-12=x\\\\\Rightarrow x+3y=12

Hence, Required equation : x+3y=12

8 0
3 years ago
Find the midpoint of the line segment JK if j (4,6) and k(0,-4)
Snowcat [4.5K]

Answer:

(2,1)

General Formulas and Concepts:

Order of Operations: BPEMDAS

Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define points</u>

J (4, 6)

K (0, -4)

<u>Step 2: Find midpoint</u>

  1. Substitute:                         (\frac{4+0}{2},\frac{6-4}{2})
  2. Add/Subtract:                    (\frac{4}{2},\frac{2}{2})
  3. Divide:                               (2,1)
4 0
3 years ago
I need help with this question?
Delicious77 [7]
If I remember right the answer is c
5 0
3 years ago
F(x) = x + 2 when x = 10
murzikaleks [220]

Answer:

f(10) = 12

Step-by-step explanation:

f(x) = x + 2

Substitute x for 10.

f(10) = 10 + 2

f(10) = 12

8 0
3 years ago
Read 2 more answers
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