Find the distance BF for the points B(1,-1) and F(-3,5)

In a recent game, Syler played 4 minutes of each period. The four periods

Rus_ich [418]

Answer: 25%

Step-by-step explanation:

6 0

3 years ago

The sum of two segments are 75 cm, and one the segments are four times the other. Calculate the measurement of each segment

iVinArrow [24]

The length of one segment is 15 cm and other segment is 60 cm

Step-by-step explanation:

Let x be the length of one segment and y be the length of other segment

Then according to given statement

x+y=75 Eqn 1

And

one the segments are four times the other

x=4y Eqn 2

$Putting\ x=4y\ in\ equation\ 1$

$4y+y=75\\5y=75\\Dividing\ both\ sides\ by\ 5\\\frac{5y}{5}=\frac{75}{5}\\y=15\\Putting\ y=15\ in\ eqn\ 2\\x=4(15)\\x=60$

Hence,

The length of one segment is 15 cm and other segment is 60 cm

Keywords: Linear Equation, Variables

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0

3 years ago

PLEASE HELP!!!! PRQ = ?

zhannawk [14.2K]

PRQ=VXW

I think! I hope this helps!

7 0

3 years ago

List the next three numbers for the sequence: 25, 75, 300, 1500, ...

ELEN [110]

Answer: 2000

Step-by-step explanation:

4 0

3 years ago