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oksian1 [2.3K]
3 years ago
11

Someone help will mark rbainliest

Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

answer is x = 6

9-3=6

so x=6

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At Adam's Hats, there are 52 baseball caps and 13 other hats. What percentage of the hats are baseball caps?
Solnce55 [7]

Total hats = 52 + 13 = 65

Percentage that are baseball = number of baseball/ total hats x 100.

52/65 = 0.8 x 100 = 80%

80% are baseball hats

3 0
3 years ago
How many integers between 2020 and 2400 have four distinct digits arranged in increasing order?
malfutka [58]

Answer:  E=15

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Sorry if it is incorrect

8 0
3 years ago
Read 2 more answers
A box contains 12 chocolates, 3 of which are white chocolate, 4 milk chocolate, and 5 dark chocolate. I am sharing the box with
Kay [80]

Answer:

Step-by-step explanation:

Given that a box contains 12 chocolates, 3 of which are white chocolate, 4 milk chocolate, and 5 dark chocolate.

a)  the chance that I draw a dark chocolate

b) Given that none of my friends draws a dark chocolate,  the chance that I draw a dark chocolate is

\frac{5}{9} since now all 5 dark chocolates would be there and total changed to 9 because 3 friends took 1 each.

c) All four drawn milk chocolates would be

\frac{4C4}{12C4} \\=\frac{1}{495}

d) the chance that the friend who gets to select first draws a dark chocolate and I draw a dark chocolate too

=P(first friend draws a dark chocolate) * P(I draw a dark chocolate)

When it comes to me chances are either there are 4 dark, or 3 dark, or 1 dark depending upon the other two friends drew black or not

= \frac{5}{12} *\frac{7}{11} *\frac{6}{11} +2(\frac{5}{12} *\frac{4}{11} *\frac{7}{11} ) +\frac{5}{12} *\frac{4}{11} *\frac{4}{11} \\= \frac{140+280+80}{1452} \\=\frac{500}{1452} \\=\frac{125}{363}

4 0
3 years ago
If a cordinate set (x,y) has two different scale factors this is a valid transformation..
mafiozo [28]
I’m going to say A.yes but I’m not sure sorry.
6 0
3 years ago
Which conic section does the equation below describe? <br> x^2+y^2+2x-8y-13=0
Gre4nikov [31]

Answer:  B) Circle

<u>Step-by-step explanation:</u>

First, complete the square:

x² + 2x + <u>  1   </u>  + y² - 8y + <u>  16  </u> = 13 + <u>  1  </u> + <u>  16  </u>

       ↓       ↑             ↓         ↑

   (2/2) = (1)²          (-8/2) = (-4)²

       (x + 1)²    +             (y - 4)²   =  30

The result is a circle whose center is (-1, 4) and radius is √30

3 0
3 years ago
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