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schepotkina [342]
3 years ago
7

A company needs to make at least A company needs to make at least 75,000 bottles 20-oz bottles can made from 1 pound if plastic

new plastic cost $.83/pound recycled plastic cost $.55/pound determine the economic Impact of using more materials and or recycled materials
Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0

Answer:

By using the recycled plastic the company will save $1050.

Step-by-step explanation:

A company needs to make at least 75,000 bottles.

Now, 20-oz bottles can be made from 1 pound.

Then, 75000-oz bottles can be made from \frac{75000}{20} = 3750 pounds of plastic.

Now, the cost of new plastic is $0.83 per pound.

So, cost of new plastic to make 75000 bottles will be $(3750 × 0.83) = $3112.5.

Again,  the cost of recycled plastic is $0.55 per pound.

So, cost of recycled plastic to make 75000 bottles will be $(3750 × 0.55) = $2062.5.

Therefore, by using the recycled plastic the company will save $(3112.5 - 2062.5) = $1050. (Answer)

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Esta pregunta esta incompleta

Pregunta completa

Se necesitan conductores voluntarios para llevar a 80 estudiantes al juego de béisbol del campeonato. Los conductores cuentan con automóviles, con capacidad para 4 estudiantes, o camionetas, con capacidad para 6 estudiantes. La ecuación describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes.

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b) c = 14 y v = 4 son un par de soluciones de la ecuación.

c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.

d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.

e) Si pasan 20 autos, no se necesitan camionetas.

f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.

Answer:

La opción b, e y f.

Step-by-step explanation:

Pasando por las opciones dadas:

c = coches que pueden llevar a 4 estudiantes

v = furgonetas con capacidad para 6 estudiantes

a) Si van 12 coches, se necesitan 2 furgonetas.

= 12 (4) + 2 (6)

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= 60

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La opción a es incorrecta

b) c = 14 y v = 4 son un par de soluciones de la ecuación.

14 (4) + 4 (6)

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La opción b es correcta

c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.

Por lo tanto:

5 (4) + 11 (6)

= 20 + 66

= 86.

86 es mayor que 80, la opción c es correcta, habría un espacio adicional para 6 estudiantes.

d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.

Por lo tanto:

10 (4) + 8 (6)

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= 88

e) Si pasan 20 autos, no se necesitan camionetas.

20 (4) = 80 estudiantes

La opción e es correcta

f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.

8 (6) + 8 (4)

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La opción b es correcta

Por lo tanto, la ecuacióna que describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes es la opción b, e y f.

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