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victus00 [196]
3 years ago
6

Help please! Thank you!!

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

i dont know what it is

Step-by-step explanation:

maybe a

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Two numbers have a distance of 6 units from 0 on a number line. The numbers can be graphed on the number line as points A and B.
lara [203]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
How do you solve the following equation: 5-(2x-3)=-8+2x
kirza4 [7]
I believe it would be done like this:
subtract 2x-8 from both sides. then use cubric formula.
answer should be  x= 1.688242

4 0
4 years ago
WILL MARK BRAINLIEST IF CORRECT❤️❤️<br> Simplify the expression -5+i/2i<br> Step by step
zhenek [66]

Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

product = 36 - 25i^2

= 36 -(-25) = 61

Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

(-5+i)/(2i)

= (-5+i)/(2i) *i/i

= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2

5 0
3 years ago
Read 2 more answers
How much is 14 kg 450 gram less than 20 kg​
Ipatiy [6.2K]
The answer.
14kg 450gram - 20kg = 5kg 550gram
Please make me the brainliest
4 0
3 years ago
Read 2 more answers
Work out the angle of elevation from the
insens350 [35]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:Angle \:\: of \:\: elevation= 30°

____________________________________

\large \tt Solution  \: :

Let the angle of elevation be " x "

\qquad \tt \rightarrow \:  \cos(x)  =  \dfrac{9 \sqrt{3} }{18}

\qquad \tt \rightarrow \:  \cos(x)  =  \dfrac{ \sqrt{3} }{2}

\qquad \tt \rightarrow \: x =  \cos {}^{ - 1}  \bigg( \cfrac{ \sqrt{3} }{2} \bigg )

\qquad \tt \rightarrow \: x = 30 \degree \:  \:  or \:  \:  \cfrac{ \pi}{6}   \:  \: rad

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
Read 2 more answers
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