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larisa [96]
3 years ago
14

23. Why would an astronomical unit not be used to measure distances on Earth?

Physics
1 answer:
Rashid [163]3 years ago
3 0
One Astronomical Unit is the distance between the Earth and the Sun, this acts as a sort of a cosmic metre stick. Astronomers don't and cannot measure distances. Distances are merely inferred from what actually has been measured, such as an angle, a relative luminosity, a time period
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A 320-g ball and a 400-g ball are attached to the two ends of a string that goes over a pulley with a radius of 8.7 cm. Because
Gnom [1K]

To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that

F = ma

Where,

m = mass

a = Acceleration (Gravitational acceleration when there is action over the object of the earth)

Torque, as we know, is the force applied at a certain distance, that is,

\tau = F*d

Where

F= Force

d = Distance

Our values are given as,

m_1 = 0.32Kg

m_2 = 0.4Kg

d = 8.7*10^{-2}m

Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say

\tau = T_2-T_1

\tau = F_2*d-F_1*d

\tau = m_2g*d-m_1*g*d

\tau = (m_2-m_1)g*d

\tau = (0.4-0.32)(9.8)(8.7*10^{-2})

\tau = 0.068N\cdot m

Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is \tau = 0.068N\cdot m

8 0
3 years ago
If a current of 2. 4 a is flowing in a wire of diameter 2. 0 mm, what is the average current density?
HACTEHA [7]

The average current density is 7.6 × 10⁵ A/m².

To calculate the current density current will be 2.4 A.

Diameter of a wire = 2mm.

The cross-sectional area of the wire is given by r = d/2

where r is the radius of the wire.  

Then, the cross-sectional area is = 0.00000314159265

                                                                   = 3.1 × 10⁻⁶ m².

<h3>What is average current density?</h3>

         Consider a current carrying conductor, the current density depends upon  the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.

Average current density j = I / A Ampere/ meter².

By substituting the values in the formula,

             j = 2.4 / ( 3.1 × 10⁻⁶)

               = 7.6 × 10⁵ A/m².

Hence, the current density can be calculated.

Learn more about average current density,

brainly.com/question/3981451

#SPJ4

5 0
2 years ago
Which of the following would most likely utilize a particulate control device?
Alexandra [31]

Answer:

d

Explanation:

Correct answer: D). All of the above The particulate control device is a device that is used for the separation of the material that is of a bigger size as compared to filter. In the factory smokestack, the particulate control device filters the particulate matter that is known to cause air pollution. In the vacuum cleaner, a fine dust particle is filtered out. In the laundry dryer, the water and dirt molecule is allowed to pass through it. Hence, all the options are correct.so therefore your answer would be all

3 0
3 years ago
Read 2 more answers
Find time when boy catches the girl or when they are at their closest separation..
soldier1979 [14.2K]

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\implies{Time=10\:sec\:and\:30\:sec}}} \\\\

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}} \\ \\

\green{\underline{\bold{Given :}}}  \\ \\   \:\:\:\: \bullet\:\:\tt\red{ Velocity \: of \: boy = 50 \: m/s} \\  \\   \:\:\:\: \bullet\:\: \tt\orange{Velocity \: of \: girl = 30 \: m/s }\\  \\  \:\:\:\: \bullet\:\:\tt\green{ Acceleration \: of \: boy =  {1 \: m/s}^{2}} \\  \\  \:\:\:\:\bullet\:\: \tt\blue{Acceleration \: of \:girl=  {2\: m/s}^{2} }\\  \\ \:\:\:\: \bullet \:\:\tt\purple{Sepration \: between \: them = 150 \: m }\\ \\  \\ \red{\underline{\bold{To \: Find :}}} \\ \\  \:\:\:\: \bullet\:\: \tt\blue{Time \: taken \: to \: catch \: the \: girl  }\\

<u>According to given question</u> :

\\ \green{\star} \:  \text{Using \: relative \: motion \: method} \\  \\  \green{ \circ} \:  \tt Net \: velocity = 50 - 30 = 20 \: m/s \\  \\ \green{ \circ} \:  \tt Net \: acceleration = 1 - 2 = - 1\: m /{s}^{2}  \\\\  \\  \star\:\bold\red{\underline{\:As \: we \: know \: that\:}} \\\\  \tt\purple{:  \implies s = ut +  \frac{1}{2}  {at}^{2}}  \\  \\ \tt\green{:  \implies 150 = 20 \times t +  \frac{1}{2}  \times  -1 \times  {t}^{2}}  \\  \\ \tt\purple{:  \implies 300 = 40t -  {t}^{2}}  \\  \\ \tt\green{:  \implies  {t}^{2}  - 40t  + 300 = 0} \\  \\ \tt\purple{:  \implies t =  \frac{  - ( - 40) \pm\sqrt{ { (- 40)}^{2}  - 4 \times 1 \times 300} }{2 \times 1}  }\\  \\ \tt\green{:  \implies t =  \frac{40 \pm \sqrt{1600 - 1200} }{2}  }\\  \\ \tt\purple{:  \implies t =  \frac{40 \pm 20}{2}  }\\  \\  \green{\tt:  \implies t = 10 \: sec \: and \: 30 \: sec}

7 0
3 years ago
A particle moves along line segments from the origin to the points (2, 0, 0), (2, 3, 1), (0, 3, 1), and back to the origin under
GenaCL600 [577]

Answer:

the net work is zero

Explanation:

Work is defined by the expression

        W = F. ds

Bold type indicates vectors

In this problem, the friction force does not decrease, therefore it will be zero.

Consequently for work on a closed path it is zero.

The work in going from the initial point (0, 0, 0) to the end of each segment is positive and when it returns from the point of origin the angle is 180º, therefore the work is negative, consequently the net work is zero

6 0
3 years ago
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