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3 years ago

Out line two application of reflactive index

Physics

1 answer:

fredd [130]3 years ago

5 0

Explanation:

In addition, they are used as light emitting diodes, optical waveguides, optical filters, piezoelectric devices, multimeter sensors, electron-beam pumped lasers, spintronics, quantum computing, electrophotography and photo-catalysis.

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When did agriculture first began?

timofeeve [1]

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Humans invented agriculture between 7,000 and 10,000 years ago, during the Neolithic era, or the New Stone Age. There were eight Neolithic crops: emmer wheat, einkorn wheat, peas, lentils, bitter vetch, hulled barley, chickpeas, and flax.

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3 years ago

Read 2 more answers

What is the wavelength of a 100 mhz radio signal?

Daniel [21]

100 MHz = 100,000,000 Hz = 10^8<span> Hz

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3 years ago

Some machines do not multiply the force that is applied to them

Katyanochek1 [597]

Answer:

Machine Efficiency

Explanation:

Efficiency is the percent of work put into a machine by the user (input work) that becomes work done by the machine (output work). The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, efficiency is always less than 100 percent

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3 years ago

Your high beam headlights illuminate the road in front of you for __________ feet. A. 150 B. 450 C. 650

ASHA 777 [7]

Answer:

B. 450 feet

Explanation:

Due to the angle at which high beam headlights illuminate, they can illuminate the road for about 450 feet.

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3 years ago

Cole is riding a sled with initial speed of 5 m/s from west to east. the frictional force of 50 n exists due west. the mass of t

stepan [7]

We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
$F=ma$
where $F=-50 N$ is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
$a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2$

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
$a= \frac{v_f^2-v_i^2}{2d}$
where
$v_f=0$ is the final speed of the sled
$v_i=5 m/s$ is the initial speed
$d$ is the distance covered

By rearranging the equation, we find d:
$d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m$

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3 years ago

Out line two application of reflactive index​

Out line two application of reflactive index