Answer:
A) Three hole punch and either a layered plastic or paper
B) Identify the lengths involved ,
Length of input arm / length of output arm = L1/ L2
Explanation:
<u>a) Materials involved includes :</u>
Three hole punch and either a layered plastic or paper
Identify the forces acting on the three-hole punch which are Input and output forces
Identify the points where they act
<u>B) procedures involved </u>
The mechanical advantage = output force / input force
step one: Identify the lengths involved
assuming no friction or relatively small friction \
mechanical advantage can be calculated as : Length of input arm / length of output arm = L1/ L2
Power is the amount of work done over a period of time. If you will put that into an equation, the formula of power will be:
P = W/t
Where:
P = power
W=work
t = time
Your problem already provides you with work and time so all you need to do is divide:
P = W/t
P = 50J/30s
P = 1.67 W
Answer:
<h3>1.43m/s²</h3>
Explanation:
According to newtons second law.
F = mass * acceleration
If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg
Force applied = 1N
acceleration = Force/mass
Substitute the values and get acceleration
acceleration = 1/0.7
acceleration = 1.43m/s²
Hence the magnitude of the acceleration of the robot is 1.43m/s²
Answer:
(a)
M = 1.898 x 10^27 kg
(b)
v = 13.74 km/s
(c) E = 0.28 N/kg
Explanation:
Time period, T = 3.55 days = 3.55 x 24 x 3600 second = 306720 s
Radius, r = 6.71 x 10^8 m
G = 6.67 x 10^-11 Nm^2/kg^2
(a) 


M = 1.898 x 10^27 kg
(b) Let v be the orbital velocity


v = 13739.5 m/s
v = 13.74 km/s
(b) The gravitational field E is given by


E = 0.28 N/kg
Answer: A piston-filling fountain pen has a piston — just like in a car — inside the barrel. This piston goes down to expel air or ink and then back up, pulling ink into the barrel. The typical process is very simple, assuming the pen is clean and dry: Push the piston down, expelling any air in the barrel