We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
Answer:
- 0.83
- 0.9
- steeper than
- slower than
Step-by-step explanation:
Letting t=1 in Ted's equation, we find that he climbs 5/6 stairs in 1 second. As a decimal, 5/6 ≈ 0.83.
Michael climbs 9 stairs in 10 seconds so his rate is ...
... (9 stairs)/(10 seconds) = (9/10) stairs/second = 0.9 stairs/second
Michael's graph will be a line with a slope of 0.9; Ted's graph will be a line with a slope of about 0.83, so the line on Michael's graph is steeper.
Ted climbs fewer stairs per second, so his rate is slower than Michael's.
_____
<em>Comment on the problem</em>
You're being asked to compare two different rates that are associated with two different people. First the comparison is one way, then it is the other way. This can be confusing. It might be helpful to draw and label a simple chart to help you keep it straight. (The attachment is such a chart scribbled on a bit of scratch paper. It is sufficient for the purpose.)
Define the formula for the surface area of a square pyramid.
A square pyramid has a square base and four triangular sides.
The formula for this case is:
A = s ^ 2 + 2 * s * L
Where,
s: side of the base
L: inclined height
The inclined height is:
L = root (h ^ 2 + (s / 2) ^ 2)
Where,
L = root (12 ^ 2 + (12/2) ^ 2)
L = root (144 + 36)
L = root (180)
L = 13.42
Substituting values:
A = (12) ^ 2 + 2 * (12) * (13.42)
A = 466.08 in ^ 2
Answer:
The surface area is:
A = 466.08 in ^ 2
