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sleet_krkn [62]
2 years ago
9

In ΔPQR, r = 4.9 cm, ∠R=21° and ∠P=104°. Find the length of p, to the nearest 10th of a centimeter.

Mathematics
2 answers:
Galina-37 [17]2 years ago
4 0

Answer:7 +7=14/8Step-by-step explanation:

Ray Of Light [21]2 years ago
3 0

Answer:

Step-by-step explanation:

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Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
A rug is shaped like a parallelogram with a base of 41⁄2 ft. and a height of 2 1⁄4 ft. What is the area of the rug? Draw and lab
Bess [88]

Answer:

46.125 square feet or 46\dfrac{1}{8} sq. feet.

Step-by-step explanation:

The rug is shaped like a parallelogram with a base of \frac{41}{2} = 20.5 feet. and a height of 2\dfrac{1}{4} = 2.25 feet.

Now, the area of a parallelogram is given by the product of one side as the base and the perpendicular distance of that side from the opposite parallel side as height.

Now, the area of the given parallelogram is (20.5 × 2.25) = 46.125 square feet. (Answer)

7 0
3 years ago
Jacksons Mom limits the amount of time he is allowed to play video games. After Jackson plays for 9 minutes his mom tells him th
Nookie1986 [14]
30 minutes is the amount of time he has left
6 0
3 years ago
Read 2 more answers
Plz i need help walk me through it, thanks​
SVETLANKA909090 [29]

Answer:

p=36^{\circ}

Step-by-step explanation:

We can prove that a tangent will always be perpendicular to the radius touching it. So, the other angle in the diagram is 90^{\circ}.

Because all the angles of a triangle sum to 180^{\circ}, we have that p+54+90=180.

We combine like terms on the left side to get p+144=180.

We subtract 144 on both sides to get p=36.

So, \boxed{p=36^{\circ}} and we're done!

6 0
2 years ago
How do you check is the equation is a extraneous solution pr not?
vampirchik [111]

We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

<h3>What is the extraneous solution?</h3>

In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.

As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.

Let's suppose the equation is:

\rm \sqrt{x+4} = x -2

Squaring both the sides:

x + 4 = (x - 2)²

x + 4 = x² - 4x + 4

x² -5x = 0

x = 0 or x = 5

Checking for the solution by plugging in the equation;

\rm \sqrt{5+4} = 5 -2

3 = 3

\rm \sqrt{0+4} = 0 -2

2 ≠ -2

The solution x = 0 shows extraneous solution.

Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

Learn more about the extraneous solution here:

brainly.com/question/14054707

#SPJ1

6 0
2 years ago
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