Factor<br><br> -10x + 2<br><br> please answer!

Necesito esto para hoy y no entiendo

BaLLatris [955]

Operación: (+6)-(3). Piso Final: +3

Inicial: +8 Operación: (+8)+(+1) Piso final: +9

Inicial: +10 Operación: (+10)-(4) Piso final: +6

3 0

2 years ago

Can someone please help me?

Radda [10]

Answer:

44 degrees

Step-by-step explanation:

Triangles ABC and DBC are congruent (as said in the question), that would make the corresponding parts of the two triangles congruent.

4 0

2 years ago

Read 2 more answers

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago

Find the area of a regular hexagon with a base of 10 and an apothem of 20.

GarryVolchara [31]

I hope this helps you

regular hexagon =6 equilateral triangle

Area=6.(10.20/2)

Area=600

8 0

3 years ago

Read 2 more answers

Find the general solution of the given system of odes. { dx/dt =2x 2y,dy/dt =x 3y}

Mumz [18]

The general solution of the given system of odes is

$x(t)=c1c^{t} + c2e^{4t}$

$y(t)= c2e^{4t} -1/2 c1e^{t}$

In arithmetic, a system of odes equations is a finite set of differential equations. Any such device may be either linear or non-linear. Also, such a machine can be both a machine of normal differential equations or a system of partial differential equations.

the compatibility conditions of an overdetermined system of odes equations may be succinctly stated in terms of differential forms (i.e., a shape to be specific, it needs to be closed). See integrability situations for differential systems for more.

It is an elaborately based poem praising or glorifying an event or character, describing nature intellectually as well as emotionally. A traditional ode is dependent on three essential parts: the strophe, the antistrophe, and the epode. Distinct forms together with the homostrophic ode and the abnormal ode also enter.

Learn more about the system of odes here brainly.com/question/15723320

#SPJ4

3 0

1 year ago

Factor -10x + 2 please answer!