Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
y = x - 7
Step-by-step explanation:
1 Liter = 1000 mL
so....
1.5 Liter = 1500 mL
Cross multiply
18 / X = 2.4 / 28
so
18 * 28 = X (2.4)
and that becomes
504 = X * 2.4
then divide by 2.4
X = 210
Answer:12, 84 and 84
Step-by-step explanation:
since we know 3 angles of a triangle = 180 degrees
1 angle = 12 degrees
12 + x + x = 180
12 + 2x = 180
2x= 180 - 12
2x = 168
x = 168/2
x = 84 degrees
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