A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
Now we multiply it to get the polynomial
polynomial function of least degree with integral coefficients that has the
given zeros
Learn more : brainly.com/question/7619478
Answer:
79 (first blank)
131 (second blank)
157 (last blank)
Step-by-step explanation:
92-13 to get the first blank, and you get 79.
118+13 to get the second blank, and you get 131.
144+13 to get the last blank and you get 157.
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Check your work:
79+13=92
92+13=105
105+13=118
118+13=131
131+13=144
144+13=157
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I hope this helps!
-No one
4(-9*x)
Multiply the two numbers
-36x
Final answer: -36x
-13 to 0 = 13 degrees changed. 0 to 22 is 22 degrees changed. 13 + 22 = 35 degree change.
10-3 = 7.
So there was a change of 35 degrees across 7 hours
35/7 = 5 degrees per hour.
