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arsen [322]
3 years ago
9

HELLP PLEASE...... Each side of a square classroom measures 23 feet. The teacher wants to put a border around the top of the cla

ssroom that costs $1.12 per foot. How much will the border cost?
Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0

Answer:

$25.76

Step-by-step explanation:

$1.12×23ft=$25.76

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Anna lives 2.5 miles to the east of her school, and Ben lives 2 miles to the west of the same school.
Blababa [14]

Answer:

Ben's house is at the point -2.

Step-by-step explanation:

Since his house is 2 miles in the opposite direction, he would have to be -2.

4 0
3 years ago
Read 2 more answers
Renata and david want to cover the walls in one room of their house with wall paper.
valkas [14]
For this case we have the following variables:
 P = area covered by a roll of wallpaper
 w = the total area of the walls
 n = number of rolls to buy
 We write the equation for n.
 You must take into account that you can determine this amount by dividing the total area between the area covered by each roll of paper.
 We have then:
 n = w / P
 
 Answer:
 
a formula that will help them determine how much wall paper they'll need to purchase is:
 n = w / P
3 0
3 years ago
Which expression is equal to “seven more than a number multiplied by 9"?
ipn [44]

Answer:

b

Step-by-step explanation:

a: is not because in the distribution property, the answer would be for a, 9x+63.

b: yes.

c: it's subtracting, not adding. The question states adding

d: 7 is not the one being multiplied in the question, 9 is. Therefore b is right

The explaining is not good but im pretty sure it's b..

7 0
2 years ago
4[9(5-4)2] what is the answer
SVEN [57.7K]

Answer:

72

Step-by-step explanation:

5-4=1

9x1=9

9x2=18

18x4=72

4 0
3 years ago
BRAINLIEST!!!
Sonbull [250]

Answer:

\sqrt{37}

Step-by-step explanation:

The distance d between a point (m , n ) and a line in the form

Ax + By + C = 0 , is calculated as

d = \frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }

Here (m, n ) = (6, 2 ) and

6x - y = - 3 ( add 3 to both sides )

6x - y + 3 = 0 → A = 6, B = - 1, C = 3

d = \frac{|6(6)+-1(2)+3|}{\sqrt{6^2+(-1)^2} }

   = \frac{|36-2+3|}{\sqrt{36+1} }

   = \frac{|37|}{\sqrt{37} }

   = \frac{37}{\sqrt{37} } × \frac{\sqrt{37} }{\sqrt{37} }

   = \frac{37\sqrt{37} }{37} ← cancel 37 on numerator/ denominator

   = \sqrt{37}

7 0
3 years ago
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