Answer:
1 - cosΘ
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x
= 
← factor 1 - cos²Θ as a difference of squares
= 
← cancel 1 + cosΘ on numerator/ denominator
= 1 - cosΘ
Answer: Infinite solutions
Step-by-step explanation: 3x -7 = 3(x-3)+2
3x + -7 = (3)(x) + (3)(-3) + 2
3x + -7 = 3x + -9 + 2
3x - 7 = (3x) + (-7)
3x -7 - 3x = 3x - 7 - 3x
-7 + 7 = -7 + 7
0 = 0
The 4th one goes with the 1st box
The 2nd one goes with the 2nd box
The last one goes with the 3rd box
