Answer:
A. It would become a different atom.
C. Its charge would increase by 1
Step-by-step explanation:
Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.
for the volume do the equation length×width×height. so 10×4×2.75
Let's solve your equation step-by-step.
3
(
3
x
−
4
)
=
−
2
(
1
−
4
x
)
Step 1: Simplify both sides of the equation.
3
(
3
x
−
4
)
=
−
2
(
1
−
4
x
)
(
3
)
(
3
x
)
+
(
3
)
(
−
4
)
=
(
−
2
)
(
1
)
+
(
−
2
)
(
−
4
x
)
(Distribute)
9
x
+
−
12
=
−
2
+
8
x
9
x
−
12
=
8
x
−
2
Step 2: Subtract 8x from both sides.
9
x
−
12
−
8
x
=
8
x
−
2
−
8
x
x
−
12
=
−
2
Step 3: Add 12 to both sides.
x
−
12
+
12
=
−
2
+
12
x
=
10
Answer:
The correct option is c which is if this test was one-tailed instead of two-tailed, you would reject the null.
Step-by-step explanation:
a: This statement cannot be true as the p-value for a 1 tailed test is dependent on the level of significance and other features.
b: This statement cannot be true as there is no valid mathematical correlation between the p-value of the one-tailed test and the current p-value.
c: This statement is true because due to the enhanced level of significance, the null hypothesis will not be rejected.
d: This statement is inverse of statement c which cannot be true.
e: The statement cannot be true as there is no correlation between the current p-value and the p-value of 1 tailed test. The correlation exists between the values of one-tailed and two-tailed p-values.
Amount in compound interest = p(1 + r/t)^nt where p is the initial
deposit, r = rate, t = number of compunding in a period and n = period.
Here,
Amount after t years = 103(1.02)^t
i.e. 1 + r = 1.02
r = 1.02 - 1 = 0.02
Therefore, annual interest rate = 0.02 x 100 = 2%
