Answer:
6 different ways? because theres only 6 books left to put on the shelf
The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
<u>Step-by-step explanation:</u>
Let the speed of wind and speed of plane in still air are w and p km/h respectively.
The effective speed on onward journey was
................(1)
The effective speed on return journey was
..............(2)
Adding equation (1) and equation (2) we get,
⇒ 
⇒ 
⇒ 
Putting value of in we get:
⇒
⇒ 
⇒ 
Therefore ,The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
Answer:
61.90
Step-by-step explanation:
12.2+14+14+6=46.2
of semi circle
circumference of semi circle = 
d
x10 = 10
semi circle so divide by 2 = 5
5 = 15.7
46.2 + 15.7 = 61.9
Answer:
0.5 m/s
Falling at 32 feet/s
Step-by-step explanation:
For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.
For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.
Let me know if you have any questions!
Hello!
no, that is not the correct way to isolate x. you were somewhat on the right track however.
here's the correct way:
add 7 to both sides to get -3x = -6
then divide both sides by -3 to get x = 2
I hope this helps, and have a nice day!
