Total = 500.00 * (1.04)^6
Total =
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632.6</span></span></span>6
If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
The first image has a coordinate of A'(1, 6) B'(-3, 7)
<h3>How to calculate the coordinates of an image after a translation?</h3>
Translation can be defined as movement in a straight line.
Given the rule: (x,y) → (x + 3, y - 1) and A(-2,7) B(-6,8)
That means: A(x = -2, y =7) B(x = -6, y = 8)
Thus the translation will be:
A'(-2 +3, 7-1) B'(-6+3, 8-1) = A'(1, 6) B'(-3, 7)
Therefore, the coordinate of the image is A'(1, 6) B'(-3, 7)
Learn more about translation on:
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The answer should be positive 5 or 5
