Given:
Each smoothie requires 20 ounces of cranberry juice and 10 ounces of passion fruit.
There are 1260 ounces of cranberry juice.
There are 650 ounces of passion fruit juice.
For the maximum servings of the smoothie, let
x = the number of 20-ounce cranberry juice used,
y = the number of 10-ounce passion fruit juice used.
The cranberry juice runs out when
20x = 1260
x = 63 servings
The passion fruit juice runs out when
10y = 650
y = 65 servings
Because x reaches, the cranberry juice runs out first after 63 servings of the smoothie.
There will be two 10-ounces = 20 ounces of the passion fruit left.
Answer:
(a) The cranberry juice runs our first.
(b) There will be 20 ounces of the passion fruit left over.
Answer:
107 more girls will do gym on Saturday than Thursday and Friday altogether
Step-by-step explanation:
300 girls will do gym on Saturday.
100 girls did gym on Thursday
and 93 girls did gym on Friday.
now,
300 - (100 + 93)
300 - 193 = 107
$2.189 there uu go.......
Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
Answer: a. 5^42 and b 9a^6
Step-by-step explanation:
a. (5^3+4)^6
(5^7)^6 = 5^42
