Answer:
7 ÷ 4
Step-by-step explanation:
Another example would be:
12/3 = 12 ÷ 3
The number at the front will be the numerator while the second number will be the denominator
<span>Opportunity cost is the value of the next best alternative when you make a decision; it's what you give up. Understanding opportunity cost allows you to make decisions, knowing both what you are getting and what you are giving up. in the above case of lending of $500.00 to your brothers is What you want most costing $500.</span>
Get the derivative:
<em>y</em> = (9 - <em>x</em>²)¹ʹ³
d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ d/d<em>x</em> [9 - <em>x</em>²]
d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ (-2<em>x</em>)
d<em>y</em>/d<em>x</em> = -2/3 <em>x</em> (9 - <em>x</em>²)⁻²ʹ³
Evaluate it at <em>x</em> = 1 :
d<em>y</em>/d<em>x</em> (1) = -2/3 • 8⁻²ʹ³
Since 8 = 2³, we have
8⁻²ʹ³ = 1 / 8²ʹ³ = 1 / (2³)²ʹ³ = 1 / 2² = 1/4
Then the tangent line has equation
<em>y</em> - 2 = 1/4 (<em>x</em> - 1) → <em>y</em> = 1/4 <em>x</em> + 7/4
Sure, here is how I broke it down. The bird is flying a constant X miles per hour with a wind speed of Y miles per hour. So, there are two equations that you use to solve. Here they are:
X+Y=12
X-Y=4
Now, you have to use substitution or elimination to solve (I will use elimination). To use elimination, you simply add both equations together to get:
2X=16
Solve for X by dividing by 2.
X=8. We already established that X is the speed of the bird. Plug X back into either of the equations to find the windspeed.
(8)+Y=12
Subtract 8 from both sides.
Y=4. We already established that Y is the windspeed.
So, the speed of the bird (X) is 8mph and the speed of the wind (Y) is 4mph.
Hope this helped!!
Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:
b) The probability that both are defective is given by:
c) The probability that both are acceptable is given by:
d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:
e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:
f) The probability that all three are defective is given by:
