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2 years ago

Please help me out here

Mathematics

1 answer:

Sophie [7]2 years ago

5 0

Answer:

your answer is C) A negative radius does not make sense.

Step-by-step explanation:

hope it helps ^_^

You might be interested in

Solve for x: [x - 2 + 10 = 12

Monica [59]

Answer:x-2+10=12

We move all terms to the left:

x-2+10-(12)=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

Step-by-step explanation:

5 0

3 years ago

How would I solve for x?

vaieri [72.5K]

Answer:

$x = 65$

Step-by-step explanation:

First, we calculate the unknown angle of the left triangle and right triangle: $180 - 62 - 50 = 68$

Unknown angle for left triangle⬆️

$180 - 80 - 53 = 47$

Unknown angle for right triangle⬆️

Now we've calculated the two angles for the small triangle in the middle. So, we just have to calculate the top angle of the middle triangle:

$180 - 68 - 47 = 65$

The angle 65° and angle of x are vertical angle.(both are equal)

So... x= 65°

hope it helps :)

4 0

3 years ago

point P is located at (-2, 7), and point R is located at (1, 0). find the y value for the point Q that is located 2/3 the distan

natulia [17]

Answer: 7/3

Step-by-step explanation:

R-P= (3,-7). the displacement vector.

P+x(R-P) moves to x times distance between

P+(R-P) = R moves to 100% of the distance.

Q = P+2/3(R-P)

= (-2,7)+2/3(3,-7)

= (-2,7)+(2,-14/3)

= (0,7-14/3)

= (0,7/3)

= (0,2.3333...)

7 0

2 years ago

Which of the following is a radical equation? X+ V5 = 12 x² = 16 3+ x^7=13 7-14

MrRissso [65]

The second one is the correct answer

5 0

3 years ago

Plz help urgent !!!! will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

3 years ago