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rewona [7]
2 years ago
13

A point that bisects a line

Mathematics
1 answer:
a_sh-v [17]2 years ago
7 0

Answer:

D. Midpoint

Step-by-step explanation:

Bisecting means a separation directly in the middle;

A point that bisects a line will be exactly halfway along the line, which is known as the midpoint

Another way of thinking about this is:

A line segment is a kind of line, representing a portion of the line;

A parallel is also a kind of line, one that has the same gradient as another;

The 'C' option is a line itself;

The question is asking for a term that defines a point, hence none of the other 3 terms are valid as answers;

The only option that defines a point is option D

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Yakvenalex [24]

Answer:

33/8

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3 years ago
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10 mi<br> 6 mi<br> b<br> What is the length of the missing leg?<br> b<br> miles
poizon [28]

Answer:

The length of the missing leg:

  • b = 8 miles

Step-by-step explanation:

Given

  • c = 10 mi
  • a = 6 mi

To determine:

The length of the leg b = ?

For a right-angled triangle, with sides a and b the hypotenuse c is defined as:

c=\sqrt{a^2+b^2}

We can find the length of the leg b using the formula

b=\sqrt{c^2-a^2}

substituting c = 10 and b = 6 in the formula

b=\sqrt{10^2-6^2}

b=\sqrt{100-36}

b=\sqrt{64}

b=\sqrt{8^2}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

b=8 mi

Therefore, the length of the missing leg:

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6 0
3 years ago
Find the first , fourth , and eighth terms of the sequence A(n) = -3 •2 ^x - 1
Usimov [2.4K]

Answer:

A(1) = -7

A(4) = -48

A(8) = -769

Step-by-step explanation:

A(n) = -3.2 ^n - 1.....(1)\\\\Plug \: n= 1\: in \: (1)\\A(1) = -3.2 ^1 - 1 =-3.2-1= -6 -1  \\\huge\red{\boxed{A(1) = -7}}\\\\Plug \: n= 4\: in \: (1)\\A(4) = -3.2 ^4 - 1 =-3.16-1= -48 -1  \\\huge\purple{\boxed{A(4) = -49}}\\\\Plug \: n= 8\: in \: (1)\\A(8) = -3.2 ^8 - 1 =-3.256-1= -768 -1 \\\huge\orange{\boxed{A(8) = -769}}

5 0
4 years ago
Write an equation for the translation of y=3/x with asymptotes of x=7 and y=-5
Sergeeva-Olga [200]

Answer:

y = (3 / (x-7)) - 5

Step-by-step explanation:

The original equation has the asymptotes at x = 0 and y = 0.

We want to translate to the right by 7 units so that the asymptote is at x = 7 and downwards 5 units so that the asymptote is y = -5.

Now, in the first case, to move it to the right, you must subtract 7 from the independent variable (i.e. x)

And in the second case, to move a function down 5 units, subtract 5 units from the entire function.

Applying the above, the new function would be:

y = (3 / (x-7)) - 5

8 0
4 years ago
What is y=-4/3x +6. y=2
Mekhanik [1.2K]

The given equation is:
[/tex]y=-\frac{4}{3}x+6 [/tex] and we need to evaluate this for y=2.
So, first step is to plug in 2 for y in the above equation. Therefore,

2=-\frac{4}{3} x+6
2*3=-\frac{4}{3} x*3+6*3 Multiply each sides by common denominator 3
6=-4x+18
6-18= -4x Subtract 18 from each sides.
-12=-4x
-\frac{12}{-4} =-\frac{4x}{-4}
So, x=3

5 0
3 years ago
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