The formula for compound interest is:
A=P(1+r/n)^(nt)
Where A represents the amount of money in the account after t years, P is the principal (investment), n is the number of compoundings per year, and r is the interest rate in decimal form.
P=11,100
r=.031
n=12 (monthly)
t=19
A=11,100(1+.031/12)^(12*19)
A=11,100(1+. 002583)^(228)
A=11,100(1.002583)^(228)
A=11,100(1.80082)
A=$19,989.10
Answer:
Bob = 6km/h, Joe = 4km/h
Step-by-step explanation:
Bob walked 6km/h after 3 hours = 18 km
Joe walked 4km/h after 3 hours = 12 km
Finally, their distance is 30 km.
Answer:
Given: The following system:
4x + y − 2z=18 ......[1]
2x-3y+3z = 21 ......[2]
x-3y=6 ......[3]
we can write equation [3] as;
3y = x-6 ......[4]
Multiply by 3 in equation [1] to both sides of an equation we get,
or
12x+3y-6z=54 ......[5]
Substituting the equation [4] in [2] and [5] we get;
2x-(x-6)+3z=21 or
2x-x+6+3z=21
Simplify:
x+3z=15 .....[6] [combine like terms]
12x+x-6-6z =54
Simplify:
13x-6z=60 ......[7] [Combine like terms]
On Solving equation [6] and [7] simultaneously,
x+3z=15
13x-6z=60
we get the value of x
i.e, x=6
Substitute the value of x in equation x+3z=15 we get
6+3z=15 or
3z=9
Simplify:
z=3
Also, substitute the value of x=6 in equation [3] we get the value of y;
x-3y=6
6-3y=6 or
-3y = 0
Simplify:
y = 0
Therefore, the solution to the system of three linear equation is, (6, 0 , 3)