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Andrej [43]
3 years ago
6

Simplify for me please

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:

9y^4

Step-by-step explanation

i believe you just add 6yand 3y

hope this helps :)

if this is a test wait for someone else to confirm just to make sure

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DochEvi [55]

The limit of \lim_{x \to -3}\sqrt{ x^2-8} as x approaches negative 3 is 1

<h3>Limit of a function </h3>

The limit of the function given in question can also be written as:

\lim_{x \to -3}\sqrt{ x^2-8}

To determine the required limit, we will simply substitute the value of x into the function as shown:

\lim_{x \to -3}\sqrt{ x^2-8}=\sqrt{ (-3)^2-8}\\\lim_{x \to -3}\sqrt{ x^2-8}=\sqrt{9-8}=1\\

Hence the limit of \lim_{x \to -3}\sqrt{ x^2-8} as x approaches negative 3 is 1

Learn more on limit here: brainly.com/question/1444047
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