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2 years ago

Simplify for me please

Mathematics

1 answer:

Vlad1618 [11]2 years ago

8 0

Answer:

9y^4

Step-by-step explanation

i believe you just add 6yand 3y

hope this helps :)

if this is a test wait for someone else to confirm just to make sure

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Taylor is using money from her coin try to go to the fair. She wants to spend no more than $17 there. She has $8 in bills and so

ZanzabumX [31]

There are 4 quarters in dollars. Keep that in mind.

Since Taylor is spending no more than 17 dollars, she probably only has 17 dollars. We already know that she has 8 dollars in bills, so we can subtract 8 dollars from 17 dollars because we need to find the amount of dollars in quarters.

The answer for that is 9 dollars. Since there are 4 quarters in the dollars, you need to multiply 9 by 4 to find the amount of quarters.

4 0

2 years ago

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A regular hexagon is inscribed in a circle as shown determine the measure of FE

Ostrovityanka [42]

The complete question in the attached figure

we know that
1) The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm

the answer is
FE=6 cm

3 0

2 years ago

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What is the substitution of -6x-8y=-20 and x+6y=-6

ale4655 [162]

Substitution doesn't work for this, but elimination does.

-6x-8y=-20 +6( x+6y=-6)

-6x-8y=-20 + 6x+36y=-36

-6x and 6x cancel each other, add -8 and 36 to get 28, and -20 and -36 to get -56.

28y=-56

divide by 28 on both sides.

Y= -2

Then substitute y into one of the equations.

x+6(-2)=-6

x-12=-6

x=6

The ordered pair is (6,-2).

5 0

2 years ago

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13. Solve the following: a. 2.68 - 1.44 = b. 5.05 X 0.04 = c. 5.144 = 1.6 =

AURORKA [14]

A) 1.24 B) 0.202 and C) 3.215.

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1 year ago

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Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c

nadya68 [22]

Answer:

$A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]$ message SHOW_ME_THE_MONEY_

Step-by-step explanation:

The matrix

$A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\$

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message Decoded message message in letters by association

11 52 19 8 S H

-8 -9 15 23 O W

-13 -39 0 13 _ M

5 20 5 0 E _

12 56 20 8 T H

5 20 5 0 E _

-2 7 13 15 M O

9 41 14 5 N E

25 100 25 0 Y _

Then the message decoded is SHOW_ME_THE_MONEY_

3 0

2 years ago