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Romashka-Z-Leto [24]
3 years ago
11

A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one

loan for $3000 repayable in 12 months?
Mathematics
1 answer:
RSB [31]3 years ago
8 0

A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one loan for $3000 repayable in 12 months?

He took two different loans, it charged him loan processing fee twice, two-time documentation process, and of course, extra time spent for second loan. Instead, he could take single loan of $3000 with one-time processing fee, one-time documentation process, and time-saving also.

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What are the solutions of the equation y = negative 2 x squared + 9 x minus 4 shown in the graph below? On a coordinate plane, a
katovenus [111]

Answer:

c

Step-by-step explanation:

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2 years ago
Jen plans to tile the kitchen floor. Each time covers 3 square meters. The kitchen is 4 5/6 meters wide and 5 meters long. How m
Stells [14]

Answer:

Jen needs approximately 8 tiles to cover the kitchen floor

Step-by-step explanation:

What we want to calculate here is the number of tiles needed to cover the kitchen floor.

The first thing we need to do here is to calculate the area of the kitchen floor.

Mathematically, that would be the product of the length of the kitchen floor and the length of the width.

That is; 4 5/6 * 5 = 29/6 * 5 = 145/6 m^2

Now, to calculate the number of tiles needed, we only need to divide the area of the kitchen floor by the area of the individual tiles

Mathematically, that would be;

145/6 ÷ 3 = 145/6 * 1/3 = 145/18 = 8.05556

This is approximately 8 tiles

5 0
3 years ago
Please Help Fast It’s Pretty Easy a sew both question please and thank you
Romashka [77]

Answer:

5x-10=60 being vertically plopposite angle .

8 0
3 years ago
Read 2 more answers
If a random sample of 47 steel bolts is selected, what is the probability that the sample mean would differ from the population
Luba_88 [7]

Complete Question

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 143 millimetres, and a standard deviation of 5. If a random sample of 47 steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 0.2 millimetres? Round your answer to four decimal places.

Answer:

The probability is P(|\= x - \mu | \ge 0.2 ) = 0.78394

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  47

    The mean diameter is \mu = 143

    The standard deviation is \sigma  = 5

Generally the standard error of the mean is mathematically represented as

       \sigma_{x} = \frac{\sigma }{\sqrt{n} }

=>     \sigma_{x} = \frac{5 }{\sqrt{47} }

=>     \sigma_{x} = 0.7293

Generally the probability that the sample mean will differ from the population mean by more than 0.2 milli meters is mathematically represented as

       P(|\= x - \mu | \ge 0.2 ) = P(\frac{|\= x - \mu|}{\sigma_{x}} \ge \frac{0.2}{0.7293}  )

\frac{|\= x - \mu | -\mu}{\sigma }  =  |Z| (The  \ standardized \  value\  of  \ {|\= x - \mu |  )

=>      P(|\= x - \mu | \ge 0.2 ) = P(|Z| \ge 0.2742 )

=>     P(|\= x - \mu | \ge 0.2 ) = P(Z < - 2742) + P(Z > 0.2742)

From the z table  the area under the normal curve to the left corresponding to   -2.742  is

    P(Z < -0.2742) =0.39197

From the z table  the area under the normal curve to the right corresponding to   2.742  is        

    P(Z > 0.2742)   =  0.39197

So

      P(|\= x - \mu | \ge 0.2 ) = 0.39197 + 0.39197

      P(|\= x - \mu | \ge 0.2 ) = 0.78394

7 0
3 years ago
The sign of the product of –35 and –625 is .
harina [27]

Answer:

21875

Step-by-step explanation:

-35 x (-625) = 21875

7 0
3 years ago
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