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3 years ago

62\100 simplest form 45\100 simplest form

Mathematics

2 answers:

lapo4ka [179]3 years ago

8 0

Answer:

62/100 = 31/50

45/100 = 9/20

Step-by-step explanation:

62 and 100 have a greatest common factor of <em>2. </em>We can use this to break the fraction 62/100 apart:

$\dfrac{62}{100}=\dfrac{2\times31}{2\times50}=\dfrac{2}{2}\times\dfrac{31}{50}=\dfrac{31}{50}$

We can do the same to simplify 45/100. The greatest common factor of 45 and 100 is <em>5</em>, so following the same process:

$\dfrac{45}{100}=\dfrac{5\times9}{5\times20}=\dfrac{5}{5}\times\dfrac{9}{20}=\dfrac{9}{20}$

vlabodo [156]3 years ago

5 0

Answer:

62/100= 31/50

45/100= 9/20

Step-by-step explanation:

Divide 62 and 100 by two to simplify

Divide 45 and 100 by 5 to simplify

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Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

2 years ago

Suppose there is no outcome common to all three of the events A, B, and C.

mina [271]

Answer:

Yes, the event are mutually exclusive...

Step-by-step explanation:

Event are mutually exclusive if those event cannot occur at the same time. That is the definition of mutually exclusive for instance in a football match, a certain team canot score 0 and 2goals in a match, it is either he scored 2goals or zero goals... In a throw of a coin we cannot have head and tail at the same time, it is either we have a head or a tail, all the event are mutually exclusive.

Now if we have a dealer selling blue car and two doors car. Let say 20% are blue and 10% have two doors. Then, this are not mutually exclusive because we can have a car that is blue and have two doors.

Mutually exclusive events are like disjoint set in SET theory, where A intersection B intersection C is equal to empty set.

Where A n B n C= {} empty set

6 0

3 years ago

Can someone help and show how this is done

blondinia [14]

Answer:

18x+5

Step-by-step explanation:

Rhe perimeter of a triangle is the sum of its three sides which here are (6x-3), (5x+6), (7x+2).

So we add them all up, 6x-3+5x+6+7x+2=18x+5

8 0

3 years ago

Read 2 more answers

Lester worked 12 hours last week at the grocery store and earned $93.00. If he continues to earn the same hourly pay, how many a

Firdavs [7]

Answer:

8 hours

Step-by-step explanation:

We can use a ratio to solve

12 hours x hours

---------- = ------------

93 dollars 62 dollars

Using cross products

12 * 62 = 93x

Divide each side by 93

12*62/93 = 93x/93

8 = x

8 hours

7 0

3 years ago

Awarding 90 Points

Amanda [17]

Answer:

1090

Step-by-step explanation:

<h3>Given AP </h3>

a₁₂ = 62
a₂₀ = 102

S₂₀

<h3>Solution</h3>

a₁₂ = a + 11d = 62
a₂₀ = a + 19d = 102

<u>Subtract the first equation from the second one:</u>

8d = 40
d = 5

a + 11*5 = 62
a = 62 - 55
a = 7

<u>Find the sum of the first 20 terms:</u>

S₂₀ = 1/2*20(a + a₂₀) = 10(7 + 102) = 10(109)= 1090

5 0

2 years ago