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OLEGan [10]
2 years ago
10

62\100 simplest form 45\100 simplest form

Mathematics
2 answers:
lapo4ka [179]2 years ago
8 0

Answer:

62/100 = 31/50

45/100 = 9/20

Step-by-step explanation:

62 and 100 have a greatest common factor of <em>2. </em>We can use this to break the fraction 62/100 apart:

\dfrac{62}{100}=\dfrac{2\times31}{2\times50}=\dfrac{2}{2}\times\dfrac{31}{50}=\dfrac{31}{50}

We can do the same to simplify 45/100. The greatest common factor of 45 and 100 is <em>5</em>, so following the same process:

\dfrac{45}{100}=\dfrac{5\times9}{5\times20}=\dfrac{5}{5}\times\dfrac{9}{20}=\dfrac{9}{20}

vlabodo [156]2 years ago
5 0

Answer:

62/100= 31/50

45/100= 9/20

Step-by-step explanation:

Divide 62 and 100 by two to simplify

Divide 45 and 100 by 5 to simplify

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Given:

A figure in which a transversal line t intersect the two parallel lines a and b.

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Solution:

If a transversal line intersect the two parallel lines, then

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2. Alternate interior angles are equal.

3. Alternate exterior angles are equal.

Now,

m\angle 1+99^\circ=180^\circ              (Linear pair)

m\angle 1=180^\circ-99^\circ

m\angle 1=81^\circ

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m\angle 3=\angle 1=81^\circ                (Vertically opposite angles)

m\angle 4=99^\circ                         (Corresponding angles)

m\angle 5=\angle 3=81^\circ                (Alternate interior angles)

m\angle 6=99^\circ                         (Alternate exterior angles)

m\angle 7=\angle 3=81^\circ                (Corresponding angles)

Therefore, \angle 1=81^\circ, \angle 2=99^\circ,\angle 3=81^\circ, \angle 4=99^\circ,\angle 5=81^\circ, \angle 6=99^\circ,\angle 7=81^\circ.

8 0
3 years ago
Find the Total Surface area of a Pyramid. Its base is a regular hexagon 4cm on a side. its height is 8 cm. Round off to nearest
oksano4ka [1.4K]

Answer:

The total surface area of a regular hexagonal pyramid is 146.2 cm².

Step-by-step explanation:

The base is a regular hexagon 4cm on a side. its height is 8 cm.

The total surface area of a pyramid with regular hexagon base

A=\frac{3\sqrt{3}}{2}a^2+3a\sqrt{h^2+\frac{3a^2}{4}

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The area of given regular hexagonal pyramid is

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A=\frac{3\sqrt{3}}{2}(16)+12\sqrt{64+12}

A=24\sqrt{3}+12\sqrt{76}

A=146.182794027

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The total surface area of a regular hexagonal pyramid is 146.2 cm².

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