Step-by-step explanation:
From the looks of it, it seems that you're factoring out the greatest common factor. I gotcha covered.
The square boxes are the biggest common factors in those equations. Hopefully, this helps!
Graph: y=-4sin(2x)+1 where the x axis starts at 30
1 answer:
Answer:
We want to graph:
y = -4*sin(2*x) + 1
Such that the x-axis starts at x = 30
This is trivial to do if we use a program to graph or if we graph by hand, here we just need to draw the x-axis such that it crosses the y-axis at the point (30, 0)
Then let's graph the equation in that axis, we will get an image like the one you can see below.
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Answer:
C) The solution for the given system of equations are A(0,-5) and B(-4,3)
Step-by-step explanation:
The given system of equation are :
from equation 2, we get y = -5 - 2x .
Put the above value of y in the equation (1).
We get:
By ALGEBRAIC IDENTITY:
or,
or,
⇒ x = 0 or, x = -20/5 = -4
So, the possible values for x are: x = 0 or x = -4
If x = 0, y = -5-2x = -5-2(0) = -5
and if x = -4, y = -5 -2(-4) = -5 + 8 = 3
Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)
Given:
The graph of a function is given.
To find:
The range of the graph.
Solution:
We know that, the domain is the set of input values and range is the set of output values.
In a graph, domain is represented by the x-axis and range is represented by the y-axis.
From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).
The graph of the function is defined over the interval . So, the domain is (-8,3].
The values of the function lie in the interval . So, the range is (-8,4].
Therefore, the range of the function are all real values over the interval (-8,4].