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3 years ago

What is 292/410 in its lowest terms?

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

4 0

Answer: 146/205

Step-by-step explanation:

292/410

divide everything by 2 (numerator and denominator)

146/205

you can not put it any simpler in fraction form

in decimal, this is the simplest form

0.712 (rounded to the nearest thousandth)

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Anit [1.1K]

First factor the numerator
b^2-6b+8/b-4 * b+8/b-2

u will get
(b-2)(b-4)/(b-4)*(b-2)*b+8
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3 years ago

A student states that Figure JKLM is congruent to Figure PQRS. Determine if the student is correct or has made an error. ;D

lyudmila [28]

Answer:

Student has made an error

Step-by-step explanation:

If two figures are said to be congruent, this implies that area of both is same and both as exactly same or copy or each other.

But from the graph, it can be stated that height of figure JKLM is 4 units whereas that of other is 6 unit.

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3 years ago

Translate the sentence into an inequality. Four subtracted from c is less than - 20 .

11Alexandr11 [23.1K]

Answer:

$\displaystyle -4 + c < -20$

Step-by-step explanation:

You could either do what I did in the above answer, or you could do this:

$\displaystyle c - 4< -20$

It does not matter how you write it, as long as you understand the concept!

I am joyous to assist you anytime.

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3 years ago

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2 years ago

If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i

navik [9.2K]

Answer: 37 units

Step-by-step explanation:

$Blue=144units^2$ This also works as the height of the triangle.

$Pink=1225units^2$ This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

$Formula: A=s^2$

$s=\sqrt[]{A}$

Let's work with Blue.

$s=\sqrt[]{144units^2} \\s=12units$

Now Pink.

$s=\sqrt[]{1225units^2}\\s=35units$

So we have a triangle with a base of 35 units and a height of 12 units.

Now let's use the pythagoream's theorem to solve.

$c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units$

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3 years ago