All categories

3 years ago

Ana uses Talk-A-Lot and Peter uses Talk-to-Me. Each company charges

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer:

They both talk for a different amount of time

You might be interested in

Differentiate. The answer is supposed to be -3/ sqrt 4-x^2

Margarita [4]

Answer:

Step-by-step explanation:

$g(x)=\cos^{-1} (\frac{x}{2})\\g'(x)= \frac{- 1}{\sqrt{1-(\frac{x}{2})^2}}*\frac{1}{2} \\=\frac{-1}{\sqrt{4-x^2} }$

6 0

3 years ago

PLEASE HELP!!!! The problem is in the photo below.

Ratling [72]

Answer :36 explanation: (39x39)-(15-15)=1296 then square root that and get 36

7 0

3 years ago

Will mark brainliest

yaroslaw [1]

Answer:

34 is it

Step-by-step explanation:

3 0

3 years ago

Find the measure of one interior angle in each regular polygon. round your answer to the nearest 10th if necessary.

Artist 52 [7]

S = (n-2) * 180
s = (14-2) * 180
s = 2160
2160/ 14 = 154.3
The answer is A

4 0

2 years ago

Read 2 more answers

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is

$A'=2\pi r^2 + \pi r^2 = 3 \pi r^2$

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

$\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r$

6 0

3 years ago