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pantera1 [17]
3 years ago
12

From the information given, find the quadrant in which the terminal point determined by t lies. Input I, II, III,

Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0
C sint & Fr; 0 and cost & gt; 0 quadrant
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4 0
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5.035 rounded to the nearest hundredth
klemol [59]

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5.04

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6 0
3 years ago
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Find the product and explain the process and reasoning step by step <br><br> $0.79 × 3.7 =
andrezito [222]

The units of the first number are "dollars." The second number has no apparent units, so we'll consider it a "pure number". This means the product will have the units of "dollars."

The two numbers together have 2+1=3 digits to the right of the decimal point(s). This means the final product will have 3 digits to the right of the decimal point. Since one of the factors is "dollars," it seems likely the result will need to be rounded to cents (2 decimal places). We'll provide the answer both ways (with 3 and with 2 decimal places.)

With these preliminaries out of the way, we have the problem of multiplying

... 79 × 37

There are numerous methods taught for finding this product. In the end, they all amount to multiplying every digit in one number by every digit in the other number and adding the results with appropriate place values. Several methods use 2-dimensional tables or arrays in their process. Here, we will use text on a line.

... 79 × 37 = (70 +9) × (30 +7)

... = 70×30 + 9×30 + 70×7 + 9×7

... = 2100 + 270 +490 + 63

... = 2100 +760 +63

... = 2860 +63

... = 2923

Putting the decimal point 3 places from the right, and adding the dollar sign gives our product:

... $0.79 × 3.7 = $2.923 ≈ $2.92

5 0
4 years ago
Read 2 more answers
Solve the question: (-4)+(-1)+2+5+...+x=437
Alex Ar [27]
The sequence is an arithmetic sequence with
a₁ = -4

d = a₂ - a₁
d = -1 - (-4)
d = -1 + 4
d = 3

an = x

Sn = 437


General formula in arithmetic sequence
Formula to find nth term
an = a₁ + d(n - 1)
Formula to find sum of sequence (sn)
Sn = n/2 (a₁ + an)

We have to make an equation system based on the problem
plug the numbers into the formula
First equation
an = a₁ + d(n - 1)
x = -4 + 3(n - 1)
x = -4 + 3n - 3
x = 3n - 7

Second equation
Sn = n/2 (a₁ + an)
n/2 (a₁ + an) = 437
n/2 (-4 + x) = 437
n(x -  4) = 874
xn - 4n = 874

Solve the equation system by subtitution method
Subtitute x with 3n - 7 in the second equation
xn - 4n = 874
(3n - 7)n - 4n = 874
3n² - 7n - 4n = 874
3n² - 11n - 874 = 0
(3n + 46)(n - 19) = 0
n = -46/3 or n = 19
Because the number of terms shouldn't be negative, -46/3 isn't required, so the value of n is 19.

Solve for x, back to the first equatin
x = 3n - 7
x = 3(19) - 7
x = 57 - 7
x = 50

The solution is 50
6 0
3 years ago
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