Write a C program to compute Matrix Multiplication of two matrices. Use one dimensional array to store each matrix, where each row is stored after another. Hence, the size of the array will be a product of number of rows times number of columns of that matrix. Get number of row and column from user and use variable length array to initialize the size of the two matrices as well as the resultant matrix. Check whether the two matrices can be multiplied or not. Write a getMatrix() function to generate the array elements randomly. Write a printMatrix() function to print the 1D array elements in 2D Matrix format. Also, write another function product(), which multiplies the two matrices and stores in the resultant matrix. With SEED 5, the following output is generated.
Sample Output
Enter the rows and columns of Matrix A with space in between: 3 5
Enter the rows and columns of Matrix B with space in between: 5 4
Matrix A:
8 6 4 1 6
2 9 7 7 5
1 3 1 1 2
Matrix B:
9 5 4 5
9 9 8 1
4 4 3 5
2 6 2 1
4 5 2 4
Product AxB:
168 146 106 91
161 186 125 81
50 52 37 22
In conclusion, the answer is 5x1
Please give Brainliest answer thanks! :)
Hello,
2x²+x-14=0
Δ=1+4*14*2=113
x=(-1-√113)/4=-2,8839...≈-2.88
or x=(-1+√113)/4=2,40753≈2.41
1) 10n
10 points per game, times however many games she plays.
2) x-15=19
x=34 (b)
x=15+19
Answer:
D
Step-by-step explanation:
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<span>Simplifying
fg + -9n = 10j
Solving
fg + -9n = 10j
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Add '9n' to each side of the equation.
fg + -9n + 9n = 10j + 9n
Combine like terms: -9n + 9n = 0
fg + 0 = 10j + 9n
fg = 10j + 9n
Divide each side by 'g'.
f = 10g-1j + 9g-1n
Simplifying
f = 10g-1j + 9g-1n</span>
