The constraint for the potential plant site 2 can be written as:

Mathematics

1 answer:

sdas [7]3 years ago

4 0

Answer:

c. x21 + x22 + x23 less or equal than 2800 y2

Step-by-step explanation:

The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.

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