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EastWind [94]
3 years ago
11

Given the function f(x) = 4x + 1, EXPLAIN and show how to find the average rate of change between x = 1 and x = 3.

Mathematics
2 answers:
Tasya [4]3 years ago
7 0
Average rate of change is another word for the slope. The function you have is presented in slope-intercept form (y=mx+b), where m=your slope. This means that you already know the slope, which is 4.

Just in case you need to show why the slope = 4, I’ll leave how to find it here:

To find the slope, use the formula: y2-y1/x2-x1

First, you need to find the y-values at x=1 and x=3. To do this, plug the x-values into the equation. The value you end up with is your y-value.

f(1) = 4(1) + 1 = 5
f(3) = 4(3) + 1 = 13

So your two points are (1, 5) and (4, 13). Now plug these points into the slope formula

m = (13-5)/(3-1) = 8/2. 8 divided by two is 4, so your average rate of change is 4. You can double check this by graphing.
11Alexandr11 [23.1K]3 years ago
4 0

The average rate of change is calculated as the slope of the line between the two points on the graph. Since at x = 1, y = -3, and at x = 3, y = 1, these are the two points which we calculate the slope from. Using the formula

m = (y2 - y1)/(x2 - x1)

m = (1 - (-3))/(3 - 1)

m = 4/2

m = 2

Therefore the slope, or the average rate of change, between these points is 2.

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3 0
3 years ago
(−7c+8d)0.6<br> write this as an equivalent equation
KengaRu [80]

-4.2c+4.8d is the answer to this equation.

8 0
3 years ago
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Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

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XP=YP for an acute triangle

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