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3 years ago

A cylinder has been cut out of a solid. Find the volume of the remaining solid. Round answer to the nearest tenth.

Mathematics

1 answer:

Vladimir79 [104]3 years ago

3 0

Answer:

98.19

Step-by-step explanation:

Volume of whole cube minus volume of cylinder. volume of cylinder is pi x r^2 x h

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Select all the expressions that equal.. *see picture for problem*

kupik [55]

Answer:

Step-by-step explanation:

oknjbgfkdfrgn jnfbfl

7 0

3 years ago

Find the next two terms of the sequence: 80, ?40, 20, ?10, ______, ______. A) 20, 40 B) 1 2 , 1 4 C) 5, ? 5 2 D) ?30, ?40

denis23 [38]

Answer:

The correct option is C) 5, 5/2

The sequence given is:

80, 40, 20, 10, _____, ______

If we look at the given numbers, it appears that every next number is obtained by dividing the previous number of 2.

Like 40 is obtained by dividing 80 by 2

$\frac{80}{2}=40$

Similarly:

$\frac{40}{2}=20$

$\frac{20}{2}=10$

$\frac{10}{2} = 5$

$\frac{5}{2}$

Therefore, the complete sequence is:

80, 40, 20, 10, 5, 5/2

Hence the correct option is C) 5, 5/2

6 0

3 years ago

Read 2 more answers

10 km, 7 km, 13 km<br> Is the triangle acute, right, or obtuse

LiRa [457]

Answer:

The triangle is acute.

Step-by-step explanation:

This is because each side is less than 90 degrees which would make the angles acute which would make the whole triangle acute.

8 0

3 years ago

PLEASE HELP

sweet [91]

The answer is 10 I just subtracted it so

5 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago