Answer:
Fill the slides with images and animations
Explanation:
these will most likely distract the audience
Unicode is a 16 bit system which can support 65636 different characters which is much more than the number of characters that ASCII code support.
Packages installed in rstudio are called from cran. cran is an online archive with r packages and other r-related resources, is the true statement.
<h3>What are
CRAN packages in R?</h3>
It comprises archives for both the most recent and prior versions of the R distribution, donated R packages, and documentation. It provides both source packages and pre-compiled binaries for Windows and macOS. there are more than 16,000 bundles available.
The version of R that is made available through CRAN is compatible with the integrated development environment for R, referred to as RStudio. All of the major systems support RStudio, which includes a variety of tools that boost productivity.
Thus, it is the true statement.
For more information about CRAN packages in R, click here:
brainly.com/question/10658169
#SPJ1
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
