False if the roots modify it’s capable of it’s attributed set
Answer:
I think it's A, def drawDiamond():
Explanation:
Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime(int bagOunces) {
if(bagOunces < 2)
cout << "Too small" << endl;
else if(bagOunces > 10)
cout << "Too large" << endl;
else
cout << 6 * bagOunces <<" seconds" << endl;
}
int main()
{
int userOunces;
cin >> userOunces;
PrintPopcornTime(userOunces);
return 0;
}
Explanation:
Inside the function PrintPopcornTime, check the parameter bagOunces using if structure. Depending on the value of bagOunces, print the required information.
Inside the main, ask the user for the userOunces. Call the PrintPopcornTime function with the userOunces.
Figure out how many people are that need the dress code and how many people that don't need the dress code. He should give the people that need dress code the dress codes.
I hope I helped you. :)
